Answer:
15
Step-by-step explanation:
2r=d
r= radius
d=diameter
diameter :30
2r=30
r=30÷2
= 15
Answer:
The numerical limits for a B grade is between 81 and 89.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

B: Scores below the top 13% and above the bottom 56%
Below the top 13%:
Below the 100-13 = 87th percentile. So below the value of X when Z has a pvalue of 0.87. So below X when Z = 1.127. So




Above the bottom 56:
Above the 56th percentile, so above the value of X when Z has a pvalue of 0.56. So above X when Z = 0.15. So




The numerical limits for a B grade is between 81 and 89.
If n=4 then plug it into the equation.
4-1
3
so your answer is 3
Step-by-step explanation:
6 I think that is the answer I hop you get it right
4a + 2c = 70 ; a = 14 ; c = 7 ; 4(14) + 2(7) = 70 ; 56 + 14 = 70 ; 70 = 70
8a + 12c = 196 ; 8(14) + 12 (7) = 196 ; 112 + 84 = 196 ; 196 = 196
Get the value of a:
4a + 2c = 70
4a = 70 - 2c
4a/4 = (70 - 2c) / 4
a = (70 - 2c) / 4
Substitute the value of a:
8a + 12 c = 196
8 ((70 - 2c)/4) + 12c = 196
(8*70)/4 - (8*2c)/4) + 12c = 196
(560 / 4) - (16c / 4) + 12c = 196
140 - 4c + 12c = 196
-4c + 12c = 196 - 140
8c = 56
8c / 8 = 56 / 8
c = 7
a = (70 - 2c) / 4
a = ((70 - 2(7))/4
a = (70 - 14)/4
a = 56 / 4
a = 14