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kumpel [21]
2 years ago
10

Three materials needed to stream video video content

Computers and Technology
2 answers:
PIT_PIT [208]2 years ago
8 0
Oh yeah yeah I don’t know ‍♂️ is
ddd [48]2 years ago
6 0

Answer:

Internet Access

Camera

streaming app

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vovikov84 [41]
<span>Yes. I think that engineers may have to adapt their original plans during the construction of systems or products</span> because they might think that other people have good ideas to make it better or because exogenous variables may require that they adapt their original plans in order to successfully construct the system. <span />
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3 years ago
I need help on this ASAP, worth 93 points
Ugo [173]

Answer:

I think I is b yeah it is b/c I took that test and u was b

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Read 2 more answers
the volume of two similar solids are 1080cm and 1715cm .if the curved surface area of the smaller cone is 840cm .fond the curved
gavmur [86]

Answer:

A_{big} = 1143.33cm^2

Explanation:

The given parameters are:

V_{small} = 1080

V_{big} = 1715

C_{small} = 840

Required

Determine the curved surface area of the big cone

The volume of a cone is:

V = \frac{1}{3}\pi r^2h

For the big cone:

V_{big} = \frac{1}{3}\pi R^2H

Where

R = radius of the big cone and H = height of the big cone

For the small cone:

V_{small} = \frac{1}{3}\pi r^2h

Where

r = radius of the small cone and H = height of the small cone

Because both cones are similar, then:

\frac{H}{h} = \frac{R}{r}

and

\frac{V_{big}}{V_{small}} = \frac{\frac{1}{3}\pi R^2H}{\frac{1}{3}\pi r^2h}

\frac{V_{big}}{V_{small}} = \frac{R^2H}{r^2h}

Substitute values for Vbig and  Vsmall

\frac{1715}{1080} = \frac{R^2H}{r^2h}

Recall that:\frac{H}{h} = \frac{R}{r}

So, we have:

\frac{1715}{1080} = \frac{R^2*R}{r^2*r}

\frac{1715}{1080} = \frac{R^3}{r^3}

Take cube roots of both sides

\sqrt[3]{\frac{1715}{1080}} = \frac{R}{r}

Factorize

\sqrt[3]{\frac{343*5}{216*5}} = \frac{R}{r}

\sqrt[3]{\frac{343}{216}} = \frac{R}{r}

\frac{7}{6} = \frac{R}{r}

The curved surface area is calculated as:

Area = \pi rl

Where

l = slant\ height

For the big cone:

A_{big} = \pi RL

For the small cone

A_{small} = \pi rl

Because both cones are similar, then:

\frac{L}{l} = \frac{R}{r}

and

\frac{A_{big}}{A_{small}} = \frac{\pi RL}{\pi rl}

\frac{A_{big}}{A_{small}} = \frac{RL}{rl}

This gives:

\frac{A_{big}}{A_{small}} = \frac{R}{r} * \frac{L}{l}

Recall that:

\frac{L}{l} = \frac{R}{r}

So, we have:

\frac{A_{big}}{A_{small}} = \frac{R}{r} * \frac{R}{r}

\frac{A_{big}}{A_{small}} = (\frac{R}{r})^2

Make A_{big} the subject

A_{big} = (\frac{R}{r})^2 * A_{small}

Substitute values for \frac{R}{r} and A_{small}

A_{big} = (\frac{7}{6})^2 * 840

A_{big} = \frac{49}{36} * 840

A_{big} = \frac{49* 840}{36}

A_{big} = 1143.33cm^2

<em>Hence, the curved surface area of the big cone is 1143.33cm^2</em>

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3 years ago
Configuring a firewall to ignore all incoming packets that request access to a specific port is known as ____.
Sati [7]

Answer: Logical Point Blocking

Explanation:

4 0
1 year ago
Telecommunications is the transmission of voice and video as well as data and usually implies transmitting a longer distance tha
saul85 [17]

Answer:

The correct answer to the following question will be "True".

Explanation:

  • Telecommunication seems to be the transmitting by cable, antenna, optical or other electromagnetic networks of signs, commands, letters, words, texts, pictures, and sounds, or knowledge of any kind.
  • This happens when the use of technologies involves the information exchange between participants in the conversation.

Therefore, the given statement is true.

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2 years ago
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