Answer:
See Explaination
Explanation:
public class testscope
{
//start of main function
public static void main(String[] args)
{
//varible declration
int i;
int x;
//loop for 10 times
for(i=0; i<10; i++)
{
//initialize value of x to 10
x = 10;
}
//the scope of variable x is visible outside of for loop
System.out.println("The value of x is: "+x);
}
}
See attachment for sample output
nb:
You can clearly see in the output of Java program the value of x is not printed and program return errors. It means the variable x declared inside for loop does not has scope outside the for loop.
Answer:
Versatility refers to the capability of a computer to perform different kinds of works with same accuracy and efficiency.
Explanation:
thank me later
The answer for this question is true
Answer:
#include<iostream>//library inclusion
using namespace std;
int main()
{
int userInput;
do//start of do while loop
{
cout << "Enter a number less than a 100" << endl;
cin >> userInput;
if (userInput < 100) //condition
{
cout << "YOu entered less than a hundred: " << userInput << endl;
}
else
{
cout << "your number is greater than 100" << endl;
}
} while (userInput > 100);//condition for do while
return 0;//termination of int main
}
Explanation:
The program has been commented for you. The do-while loop enters the first loop regardless of the condition. Then after the first iteration, it checks for the condition. If the condition is being met, it will iterate through, again. Otherwise it will break out of the loop and land on the "return 0;" line. Which also happens to be the termination of the program in this case. The if-else condition is used for the user to see when prompted.
