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Tamiku [17]
2 years ago
15

A side of the triangle below has been extended to form an exterior angle of 132°. Find the value of X

Mathematics
1 answer:
Zinaida [17]2 years ago
7 0

Answer:

x = 114°

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles, thus

x + 18° = 132° ( subtract 18° from both sides )

x = 114°

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Doesn't make sense.

Step-by-step explanation:

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75% of the temperatures are below what value? How do you know? 75% of the temperatures are above what value? How do you know? Wh
Savatey [412]

Answer:

Complete Question:

Pick a city in Maryland and determine the average high temperatures for each month. Record this in a table.

a. Create a box-and-whisker plot for the data.

b. What is the median temperature?

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Step-by-step explanation:

TASK 3

The city picked is Baltimore, the year 2017.

The table is attached in picture #1.

a) The box-and-whisker plot is attached in picture #2.

b) The median is the central value of the distribution i.e:  

42.4, 45.3, 46.8 | 54.7, 57.6, 66.0 | 69.1,  76.5,  80.6 | 85.8, 87.8, 90.0 

where we marked with a tally the quartiles.

As we have 12 values,  the average between the two central values will be the median :

M = (66.0 + 69.1) / 2 = 67.1 °F

c) 75% of the temperatures are below 83.2 °F.

Indeed, this value represents the third quartile. The position of the third quartile can be found by the formula:

3/4 · (n + 1) = 3/4 · (12 + 1) = 3/4 · 13 = 9.75

Therefore, since we did not get in integer position, the third quartile will be the average between the numbers in position 9 and 10:

q₀.₇₅ = (80.6 + 85.8) / 2 = 83.2 °F

d) 75% of the temperatures are above 50.8 °F.

Indeed, this value represents the first quartile. Similarly to point c), the position can be found by the formula:

1/4 · (n + 1) = 1/4 · 13 = 3.25

And therefore:

q₀.₂₅ = (46.8 + 54.7) / 2 = 50.8 °F. 

e) Baltimore in 2017 had a median high temperature of 67.1 °F.

25% of the year the high temperatures were warmer than 83.2 °F, with no outlier above 90.0 °F which was the hottest temperature.

25% of the high temperatures were colder than 50.8 °F, with no outlier below 42.4 °F, which was the coldest high temperature.

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Answer:

option 4

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m \angle MNO = \frac{1}{2} \times m MN\\\\

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