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aliina [53]
3 years ago
10

You blindfold your friend. You give him a bowl that contains 10 silver marbles and 6 black marbles. What is the minimum number o

f balls your friend needs to pick to be sure that they pick out all 6 black marbles
Mathematics
1 answer:
ki77a [65]3 years ago
8 0

Answer:

16 marbles.

Step-by-step explanation:

Since your friend is blindfolded the only actual way for him to be completely sure that they picked out all 6 black marbles would be to pick out all of the marbles until none are left. As long as there is even one marble in the bag then your friend will still not be sure which color it is due to being blindfolded. Therefore, under these circumstances the answer would be 16 marbles.

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Find the common difference for the following sequence and fill in the missing terms. Show all calculations. 2, 13, 24, 35, __, _
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Step-by-step explanation:

Hey there!

Given sequences are; 2 , 13 , 24 , 35 , _ , _ .

Now,

Common difference (d) = 2nd term - 1st term. = 13-2 = 11

When we subtract 1st term from 2nd term we find 11 and when we subtract 2nd term from 3rd term we get 11. This means our common difference is 11.

Now, let's find the nrh term of the sequence.

nth term= a1 + (n-1)d ( <em>a1= 1st term, d= common</em> <em>difference</em>)

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= 2 + 11n - 11

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Let's check if we have got nth term correct.

a1= 1*11 - 9 = 2

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a3 = 3*11 - 9 = 24

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So, we got our nth term.

Let's find remaining sequence.

a5= 5*11 - 9 = 46.

a6= 6*11 - 9 = 57.

Therefore, the remaining terms are : 46 and 57.

<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Step-by-step explanation:

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