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Brrunno [24]
3 years ago
7

How many 'faces' are on this square pyramid?​

Mathematics
1 answer:
qaws [65]3 years ago
7 0

Answer:

5

Step-by-step explanation:

There are 5 faces on a square pyramid

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List two primes that are consecutive natural numbers. can there be any​ others?
vlabodo [156]
Out of every two consecutive numbers one will always be even. There is only one even prime number. Whether there are an infinite number of pairs of primes which differ by two (the twin prime conjecture) is still open e.g. 3 , 5; 41 , 43 ; 101 , 103 .
3 0
4 years ago
I'm having a hard time solving this<br> May I please have an explanation
Marina CMI [18]

Answer:

e = 9

Step-by-step explanation:

ok e is just x, so we have to get it alone

4e - 10 = 2e + 8

We move the 2 since its smaller than the 4, and we move it two the other side. 4-2=2 so the new e is 2, now that 8 is alone (since we moved the 2), we cant be having the e with the -10... like this..

2e - 10 = 8, so we now add 10 so it can go with the 8, the new equation is this..

2e = 18

18/2 = 9

simple explanation

4e - 10 = 2e + 8

2e = 18

e = 9

(does that make sense)

5 0
3 years ago
Read 2 more answers
Can someone help me please In the diagram VWX and XYZ are congruent equilateral triangles, and ∠VXY is 80o. What is the measurem
mariarad [96]
Maybe if multiply 80 by 3 so you can find one of the answer then do it algebraic
5 0
3 years ago
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Paula runs a day care center. Of the last 16 children to enroll at
zalisa [80]

Answer:

0.5

Step-by-step explanation:

P(event) = number of times event occurs/ total number of trials

Hi, You are the person I answered last time!

P(event) = 8/16

8/16 simplified is equaled to 1/2.

1/2 is equaled to 0.5

Again, I'm pretty sure this is right because it says experimental probability... I hope this helps!

8 0
3 years ago
I just need help cause if I don’t I don’t know what imma do
erica [24]

Answer:

P(32) = \frac{1}{90}

P(Odd) = \frac{1}{2}

P(Multiples\ 5) = \frac{1}{5}

Step-by-step explanation:

Given

Sample Space = 10 to 99

First, we calculate the sample size (n)

n = 99 - 10 + 1

n = 90

Solving (a): P(32)

In 10 to 99, there is only 1 32.

So,

P(32) = \frac{n(32)}{n}

P(32) = \frac{1}{90}

Solving (b): P(Odd)

There are 45 odd numbers between 10 and 99

i.e.

n(Odd)  = 45

So:

P(Odd) = \frac{n(Odd)}{n}

P(Odd) = \frac{45}{90}

P(Odd) = \frac{1}{2}

Solving (c): P(Multiple of 5)

There are 18 multiples of 5 between 10 and 99

i.e

P(Multiples\ 5) = \frac{18}{90}

P(Multiples\ 5) = \frac{1}{5}

4 0
3 years ago
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