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Drupady [299]
3 years ago
14

If alpha and beta are roots of quadratic equation x^2 - p( x + 1) - c = 0 then (alpha + 1 )( beta + 1) =?

Mathematics
1 answer:
Harrizon [31]3 years ago
8 0

Answer:

Step-by-step explanation:

x²-px-p-c=0

sum of roots=α+β=-b/a=p

product of roots=αβ=c/a=-p-c

(α+1)(β+1)=αβ+α+β+1=-p-c+p+1=-c+1

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6 0
3 years ago
Use the distributive property and the diagram to match an expression that is equivalent to 12+4x.
Ket [755]

4(3+x)

This is because 4*3=12 and 4*x is 4x so you get 12+4x which is the original equation

8 0
3 years ago
Write the equation of the graph shown below in factored form. a graph that starts at the top left and continues down through the
Brut [27]

Answer:

  (d)  f(x) = (x − 3)^2(x − 2)(x − 1)

Step-by-step explanation:

In this context, a crossing of the axis at x=p means there is a factor of (x-p). A "touch" of the axis at x=q means there is a factor of (x -q)^2.

A crossing at x=1 and x=2, and a touch at x=3 means the factors are ...

  f(x) = (x -1)(x -2)(x -3)^2 . . . . . matches the last choice

8 0
2 years ago
What is the slope of the line through (-5,-10) and(-1, 5)?
Mila [183]

Answer: The slope is 15/4.

Step-by-step explanation:

M = (y2 - y1)/(x2 - x1)

M = (5 - (-10))/(-1 - (-5))

M = (5 + 10)/(-1 + 5)

M = 15/4

6 0
3 years ago
F(x)=12x2-4x-8. G(x)=11x-6
AlekseyPX

Answer: Second option.

Step-by-step explanation:

Given the functions f(x) and g(x):

f(x)=12x^2-4x-8\\\\g(x)=11x-6

You need to divide them in order to find (\frac{f}{g})(x) asked in the exercise. Then:

(\frac{f}{g})(x) =\frac{12x^2-4x-8}{11x-6}

Now, it is important to remember that, by definition, the division by zero is not defined. Therefore, the denominator of the function cannot be zero.

Let's find the value of "x" for which the denominator of the function would be zero:

1. You need to make the denominator equal to zero:

11x-6=0

2. Finally, you must solve for "x":

11x=6\\\\x=\frac{6}{11}

Therefore, as you can see, the answer is:

 (\frac{f}{g})(x) =\frac{12x^2-4x-8}{11x-6}, x=\frac{6}{11}

4 0
3 years ago
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