3 years ago

Given that sin (theta)=- V5/3 and theta is in quadrant III, solve for the exact value of cos (theta)

Mathematics

1 answer:

nadezda [96]3 years ago

4 0

Answer:

the another answer is a virus guys

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4.84 times ten to the fifth power plus 3.9 times 10 to the second power plus 8.91 times 10 to the 7th power

lakkis [162]

Okay, so you didn't really put anything for me to know what you wanted to solve, so I'm going to assume this is Scientific Notation:
We have:
10^5 = 100,000 x 4.84 would be: 484,000
10^2 = 100 x 3.9 would be: 390
10^7 = 10,000,000 x 8.91 would be: 89,100,000

3 0

3 years ago

15 points!!! Thanks in advance.

Natasha_Volkova [10]

your answer would be D.

4a (4a) + 4a (-5b) + 5b (4a) + 5b (-5b) it is simplified to 16a^2-25b^2

6 0

3 years ago

Read 2 more answers

(1 point) For the equation given below, evaluate ′ at the point (−1,2). (5−)^4+4^3=2433. ′ at (−1,2) =

ryzh [129]

Answer:

$\dfrac{343}{71}$

Step-by-step explanation:

Given the equation

$(5x-y)^4+4y^3=2433$

Find the derivative:

$((5x-y)^4+4y^3)'=(2433)'\\ \\4(5x-y)^3\cdot (5x-y)'+4\cdot 3y^2\cdot y'=0\\ \\4(5x-y)^3\cdot (5-y')+12y^2y'=0$

Substitute

$x=-1\\ \\y=2,$

then

$4(5\cdot (-1)-2)^3\cdot (5-y')+12\cdot 2^2\cdot y'=0\\ \\4(-5-2)^3(5-y')+48y'=0\\ \\4\cdot (-7)^3\cdot (5-y')+48y'=0\\ \\-1,372(5-y')+48y'=0\\ \\-6,860+1,372y'+48y'=0\\ \\1,420y'=6,860\\ \\y'=\dfrac{6,860}{1,420}=\dfrac{686}{142}=\dfrac{343}{71}$

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3 years ago

What is greater 32.725 or 32.375?

RUDIKE [14]

32.725 is greater than 32.375

8 0

3 years ago

On a pleasant Monday, the Dow-Jones Industrial average closed at 11,315. On Wednesday, it closed down twice as many points as it

kirza4 [7]

I think it lose 1533 points

6 0

4 years ago