Ask question

Ask question

All categories

3 years ago

12

The polynomial –16t2 + vt + h0 models the height, in feet, of a ball t seconds after it is thrown. In this polynomial, v represe

nts the initial vertical velocity of the ball and h0 represents the initial height of the ball. Min throws a baseball from a height of 6 feet with an initial vertical velocity of 30 feet per second. Which polynomial models the height of the ball, in feet?

2 answers:

oksian1 [2.3K]3 years ago

6 0

Answer:

D-16t^2+30t+6

Step-by-step explanation:

i got it right on ed.

mel-nik [20]3 years ago

4 0

Answer: -16t^2 + 30t + 6

Step-by-step explanation: just substitute it...also did Edge

You might be interested in

PTC is a substance that has a strong bitter taste for some people and is tasteless for others. The ability to taste PTC is inher

lana66690 [7]

Answer:

a) $n=\frac{0.76(1-0.76)}{(\frac{0.01}{1.64})^2}=4905.83$

And rounded up we have that n=4906

b) For this case since we don't have prior info we need to use as estimatro for the proportion $\hat p =0.5$

$n=\frac{0.5(1-0.5)}{(\frac{0.01}{1.64})^2}=6724$

And rounded up we have that n=6724

Step-by-step explanation:

We need to remember that the confidence interval for the true proportion is given by :

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Part a

The estimated proportion for this case is $\hat p =0.76$

Our interval is at 90% of confidence, and the significance level is given by $\alpha=1-0.90=0.1$ and $\alpha/2 =0.05$ . The critical values for this case are:

$z_{\alpha/2}=-1.64, t_{1-\alpha/2}=1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

The margin of error desired is given $ME =\pm 0.01$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Replacing we got:

$n=\frac{0.76(1-0.76)}{(\frac{0.01}{1.64})^2}=4905.83$

And rounded up we have that n=4906

Part b

For this case since we don't have prior info we need to use as estimatro for the proportion $\hat p =0.5$

$n=\frac{0.5(1-0.5)}{(\frac{0.01}{1.64})^2}=6724$

And rounded up we have that n=6724

3 0

3 years ago

1) Graph the following lines and using the graph determine several values of x for which the graph is positive (negative):

Aleksandr [31]

1) $y=-0.5x-2$

The graph of the above equation is attached in the attachment below.

For all the values from negative infinity to -4, the function is positive.

X ∈ (-∞,-4]

2) $y=-1.5x+3$

To find the x- intercept, plug y =0

$0=-1.5x+3$

$1.5x=3$

$x=2$

x intercept = (2,0)

To find the y- intercept, plug x=0

$y=-1.5(0)+3$

$y=3$

Y- intercept = ( 0,3)

3) $y=13-x$

Y- intercept = (0,13)

x- intercept = (13,0)

Area of triangle = $\frac{bh}{2}$

Area of triangle = $\frac{13\times13}{2}$

Area = $\frac{169}{2}$ sq unit.

4) The graphs of $y=-2x+7$ and $y=0.5x-5.5$ is attached in the attachment below.

The intersection point is ( 5,-3)

5) A = (-3,0)

B = (4,5)

C = (0,-4)

Slope of AB = $\frac{5-0)}{4-(-3)} =\frac{5}{7}$

Slope intercept of line $y=mx+b$

Where, m is the slope and b is the y- intercept.

Plugging point A and the slope in the y- intercept to find the value of b.

$0=\frac{5(-3)}{7} +b$

$b=\frac{15}{7}$

Equation of line AB: $y=\frac{5x}{7} +\frac{15}{7}$

Slope of BC = $\frac{-4-5}{0-4} =\frac{9}{4}$

Plug C = (0,-4)

$-4=0+b$

b=-4

equation of line BC= $y=\frac{9x}{4} -4$

Slope of line AC = $\frac{-4-0}{0--3} =\frac{-4}{3}$

Equation of line AC = $y=\frac{-4x}{3} -4$

Y intercept of AB = $(0,\frac{15}{7} )$

5 0

3 years ago

Read 2 more answers

Solve the following inequality: -20 < 4- 2x

Bas_tet [7]

Answer: The answer is x < 12 but i don't see that as an option.

7 0

3 years ago

Read 2 more answers

I need help with this<br>histogram

chubhunter [2.5K]

A is what I thinkkkk

4 0

3 years ago

The functions x) and g(x) are shown on the graph.<br>f(x) = x2<br>What is g(x)?

Nadya [2.5K]

Answer:

C. g(x) = 4x²

Step-by-step explanation:

The general equation for a parabola is

y = ax² + bx +c

Since ƒ(x) = x², a=1, b =0, c =0

For g(x), the vertex is still at the origin, so

g(x) = ax²

The graph passes through (1,4).

Insert the coordinates of the point.

4 = a(1)²

a = 4

g(x) = 4x²

The figure below shows that the graph of g(x) = 4x² passes through the point (1, 4).

6 0

3 years ago