Answer:
y= -0.40x+ 4.00
Step-by-step explanation:
The distance (d) between two points (x1,y1) and (x2,y2) is given by the formula
d = √ ((X2-X1)2+(Y2-Y1)2)
d = √ (-5-5)2+(6-2)2
d = √ ((-10)2+(4)2)
d = √ (100+16)
d = √ 116
The distance between the points is 10.770329614269
The midpoint of two points is given by the formula
Midpoint= ((X1+X2)/2,(Y1+Y2)/2)
Find the x value of the midpoint
Xm=(X1+X2)/2
Xm=(5+-5)/2=0
Find the Y value of the midpoint
Ym=(Y1+Y2)/2
Ym=(2+6)/2=4
The midpoint is: (0,4)
Graphing the two points, midpoint and distance
P1 (5,2)
P2 (-5,6)
Midpoint (0,4)
The length of the black line is the distance between the points (10.770329614269)
Find the slope of the line connecting the two points
Slope = (Y2-Y1) = (6-2) = (4) = -0.4
(X2-X1) (-5-5) (-10)
Find the equation of the line passing through the two points
The general equation for a straight line is
y = mx + b
Where m represents the slope of the line which we found in the previous step to be -0.4
y = -0.40x + b
We substitute x and y for the values from one of our points (5,2)
2 = -.40×5 + b
2 = -2.00 + b
2--2.00 = b
4.00 = b
Knowing both b and m, we can contruct the equation of the line
y= -0.40x+ 4.00
X and Y intercepts
The x-intercept is a point on the graph where y is zero
Using the equation we found in the previous step and substituting zero for y
y= -0.40x+ 4.00
0= -0.40x+ 4.00
0.40x= 4.00
x= 4.00/0.40 = 10.00
The x intercept for this straight line is 10.00
The y-intercept is a point on the graph where x is zero
Using the equation we found in the previous step and substituting zero for x
y= -0.40×0+ 4.00
y= 4.00
The y intercept for this straight line is 10.00
