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3 years ago

Last year there were 475 students at Valley Middle School. This year there are 675.

Mathematics

2 answers:

tensa zangetsu [6.8K]3 years ago

7 0

Answer:

33.35% maybe

Step-by-step explanation:

Katena32 [7]3 years ago

5 0

Answer:

approximately 42.11% increase

Step-by-step explanation:

% increase = Increase ÷ Original Number × 100

%increase = 200 ÷ 475 × 100 =42.11%

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3.Compare properties of squares and rhombi to properties of other quadrilaterals by answering each question. Write a brief expla

frozen [14]

Given:

Quadrilaterals are given.

Opposite sides are equal.

Length of the diagonals are equal.

Angles on four edges is 90 degree.

All sides are equal.

Length of the diagonals are not equal.

Opposite sides are equal.

All sides are equal.

90 degree form in the intersection of the diagonal.

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1 year ago

A cat must jump 5.5ft to clear the fence to get home

Oliga [24]

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3 years ago

Help please triangles and trig

Oksanka [162]

Answer:

$\sin L = \frac{3}{5}$

$\tan N = \frac{4}{3}$

$\cos L = \frac{4}{5}$

$\sin N = \frac{4}{5}$

Step-by-step explanation:

Given

The above triangle

First, we calculate the length LM using Pythagoras theorem.

$LN^2 = LM^2 + MN^2$

$10^2 = LM^2 + 6^2$

$100 = LM^2 + 36$

Collect like terms

$LM^2 = 100 - 36$

$LM^2 = 64$

Take positive square root

$LM=8$

Solving (a): Sin L

$\sin L = \frac{Opposite}{Hypotenuse}$

$\sin L = \frac{MN}{LN}$

$\sin L = \frac{6}{10}$

Simplify

$\sin L = \frac{3}{5}$

Solving (b): tan N

$\tan N = \frac{Opposite}{Adjacent}$

$\tan N = \frac{LM}{MN}$

$\tan N = \frac{8}{6}$

Simplify

$\tan N = \frac{4}{3}$

Solving (c): cos L

This calculated as:

$\cos L = \frac{Adjacent}{Hypotenuse}$

$\cos L = \frac{LM}{LN}$

$\cos L = \frac{8}{10}$

Simplify

$\cos L = \frac{4}{5}$

Solving (d): sin N

This is calculated using:

If $a + b = 90$

Then: $\sin a = \cos b$

So:

$\sin N = \cos L$

$\sin N = \frac{4}{5}$

8 0

3 years ago

PLEASE HELP ME ASAP!!! I WILL MAKE YOU BRAINLIEST AND YOU GET 20 points!!!

uranmaximum [27]

Answer:

I hope this makes sense, sorry for the lack of proofs.

Step-by-step explanation:

It is given that S is the midpoint of line QT. The definition of a midpoint is that it bisects the line it is on. So, line QS and line TS are congruent, or the same.

Now, we also know that line QR and line TU are parallel. Because they are parallel, it means that they form congruent corners with lines QS and TS..I think the proof here is "angles opposite to congruent sides are congruent in a triangle." But I'm not sure if this is right. Anyways, this means angles RQS and UTS are congruent.

There's also some proof that when two lines cross, the opposite angles are congruent. This means that angles TSU and QSR are congruent.

Therefore, by ASA (angle-side-angle) ΔQRS ≅ ΔTUS.

3 0

3 years ago

All of the following are equivalent except___. 7x^3,4x+3x,(4+3)x,7x

Paha777 [63]

7x^3 is not equivalent to the other varieties of 7x

6 0

4 years ago

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