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Veseljchak [2.6K]
3 years ago
14

If p is a positive integer,then p(p+1)(p-1) is always divisible by?

Mathematics
1 answer:
ElenaW [278]3 years ago
4 0

I am not quite sure what the choices are, but the answer to that problem is:

If p is a positive integer, then p(p+1)(p-1) is always divisible by “an even number”.

The explanation to this is that whatever number you input to that equation, the answer will always be an even number. This is due to the expression p(p+1)(p-1) which always result in a even product.

For example if p=3, then (p+1)(p-1) becomes (4)(2) giving you a even number.

And if for example if p=2, then (p+1)(p-1) becomes (3)(1) which gives an odd product, but we still have to multiply this with p therefore 2*3 = 6 which is even product. The outcome is always even number.

<span>Answer: From the choices, select the even number</span>

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372 picoseconds equal to how many femoseconds
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3 years ago
Suppose a basketball player has made 291 out of 389 free throws. If the player makes the next 2 free throws, I will pay you $38.
VMariaS [17]

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The expected value of the proposition is -$0.76.

Step-by-step explanation:

It is provided that a basketball player has made 291 out of 389 free throws.

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P(\text{free throw})=\frac{291}{389}=0.7481

The probability that he makes the next 2 free throws is:

P(\text{Next 2 free throws})=(0.7481)^{2}=0.5596

The payout rules are:

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Compute the expected value of the proposition as follows:

Expected value = $38 × P (Makes both) + (-$50) × P (Misses both)

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Thus, the expected value of the proposition is -$0.76.

5 0
3 years ago
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