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elena-14-01-66 [18.8K]
3 years ago
14

Which expression shows the amount would you pay if your lunch bill is X and you leave(pay) a 15% tip?

Mathematics
1 answer:
ddd [48]3 years ago
8 0

Answer:

Step-by-step explanation:

(b) is correct.  x represents the bill and 0.15 represents the 15% tip on that bill.

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23 degrees below 0, what is the answer please help
IrinaVladis [17]

Answer:

-23

Step-by-step explanation:

23 degrees below 0 is 0-23, or -23

Hope this helps plz mark brainliest :D

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How do you re-write this using only positive exponents? <br><br> 3x^-4/3 (1+2x^5/3)
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\bf \cfrac{3x^{-\frac{4}{3}}}{3(1+2x^{\frac{5}{3}})}\implies \cfrac{3}{3}\cdot \cfrac{1}{x^{\frac{4}{3}}}\cdot \cfrac{1}{(1+2x^{\frac{5}{3}})}\implies \cfrac{1}{x^{\frac{4}{3}}(1+2x^{\frac{5}{3}})}

\bf \cfrac{1}{x^{\frac{4}{3}}+2x^{\frac{5}{3}}x^{\frac{4}{3}}}\implies \cfrac{1}{x^{\frac{4}{3}}+2x^{\frac{5}{3}+\frac{4}{3}}}\implies \cfrac{1}{x^{\frac{4}{3}}2x^{\frac{9}{3}}}\implies \cfrac{1}{x^{\frac{4}{3}}+2x^3}&#10;\\\\\\&#10;\cfrac{1}{\sqrt[3]{x^4}+2x^3}\implies \cfrac{1}{x\sqrt[3]{x}+2x^3}\implies \cfrac{1}{x(\sqrt[3]{x}+2x^2)}
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4 years ago
Use the GFC to factor 45x+75
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
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Find the measures of the three angles, in radians, of the triangle with the given vertices: d(1,1,1), e(1,−5,2), and f(−2,2,7).
Oduvanchick [21]

Consider triangle DEF with vertices D(1,1,1), E(1,-5,2) and F(-2,2,7).

1. Find

\overrightarrow{DE}=(1-1,-5-1,2-1)=(0,-6,1),\\ \\\overrightarrow{DF}=(-2-1,2-1,7-1)=(-3,1,6).

Then

\cos \angle D=\dfrac{0\cdot (-3)+(-6)\cdot 1+1\cdot 6}{\sqrt{0^2+(-6)^2+1^2}\cdot \sqrt{(-3)^2+1^2+6^2}}=\dfrac{0}{\sqrt{37} \cdot \sqrt{46} }=0.

2. Find

\overrightarrow{ED}=(1-1,1-(-5),1-2)=(0,6,-1),\\ \\\overrightarrow{EF}=(-2-1,2-(-5),7-2)=(-3,7,5).

Then

\cos \angle E=\dfrac{0\cdot (-2)+6\cdot 7+(-1)\cdot 5}{\sqrt{0^2+6^2+(-1)^2}\cdot \sqrt{(-3)^2+7^2+5^2}}=\dfrac{37}{\sqrt{37} \cdot \sqrt{83} }=\sqrt{\dfrac{37}{83}}.

3. Find

\overrightarrow{FE}=(1-(-2),-5-2,2-7)=(3,-7,-5),\\ \\\overrightarrow{FD}=(1-(-2),1-2,1-7)=(3,-1,-6).

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\cos \angle F=\dfrac{3\cdot 3+(-7)\cdot (-1)+(-5)\cdot (-6)}{\sqrt{3^2+(-7)^2+(-5)^2}\cdot \sqrt{3^2+(-1)^2+(-6)^2}}=\dfrac{46}{\sqrt{83} \cdot \sqrt{46} }=\sqrt{\dfrac{46}{83}}.

4.

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3 years ago
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Answer: their product is always one

Step-by-step explanation:

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