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PilotLPTM [1.2K]
3 years ago
9

Solve the for the variable. SHOW ALL WORK/EXPLAIN EVERY STEP!!!2(x-2)-5=3-2x+6​

Mathematics
2 answers:
tiny-mole [99]3 years ago
4 0

Answer:

x=9/2

Step-by-step explanation:

First distribute 2

2x-4-5=3-2x+6

Add the like terms on the left side -4-5=-9

2x-9=3-2x+6

Do this with the right side 3+6=9

2x-9=-2x+9

Add 9 from the left side to the right side

2x=-2x+18

Then add 2x from the right side to the left side

4x=18

Divide 4 from both sides

x=18/4 or 9/2

Colt1911 [192]3 years ago
4 0

Answer:

9/2

Step-by-step explanation:

2x-4-5= 3-2x+6  distribute 2 through the parentheses

2x-4-5=9-2x     add the numbers

2x-9=9-2x calculate the difference

2x+2x-9= 9  move variable to left side and change sign

2x+2x= 9+9 move constant to right side and change sign

4x= 18  collect like terms

x=9/2 divide both sides by 4

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The measure of angle PQR when Zubin drew a circle with right triangle will be 65°.

<h3>How to find the measure of the angle?</h3>

From the information given, when Zubin drew a circle with right triangle, arc QR measures 50 degrees.

Therefore, the measure of angle PQR will be:

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Irina-Kira [14]

Answer:

The inner function is u = \pi x.

The outer function is f(u) = \tan{u}.

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Step-by-step explanation:

The inner function is the one we apply the outer function to.

So

y = \tan{\pi x}

We apply the outer function tangent to \pi x.

So, the inner function is u = \pi x.

The outer function is f(u) = \tan{u}.

The derivative of a compositve function

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y^{\prime} = f^{\prime}(u)*g^{\prime}(x)

So

f(u) = \tan{u}

f^{\prime}(u) = \sec^{2}{u}

u = g(x) = \pi x

g^{\prime}(x) = \pi

So

y^{\prime} = f^{\prime}(u)*g^{\prime}(x)

\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}

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Step-by-step explanation:

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Step-by-step explanation:

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