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3 years ago

Solve the for the variable. SHOW ALL WORK/EXPLAIN EVERY STEP!!!2(x-2)-5=3-2x+6

Mathematics

2 answers:

tiny-mole [99]3 years ago

4 0

Answer:

x=9/2

Step-by-step explanation:

First distribute 2

2x-4-5=3-2x+6

Add the like terms on the left side -4-5=-9

2x-9=3-2x+6

Do this with the right side 3+6=9

2x-9=-2x+9

Add 9 from the left side to the right side

2x=-2x+18

Then add 2x from the right side to the left side

4x=18

Divide 4 from both sides

x=18/4 or 9/2

Colt1911 [192]3 years ago

4 0

Answer:

9/2

Step-by-step explanation:

2x-4-5= 3-2x+6 distribute 2 through the parentheses

2x-4-5=9-2x add the numbers

2x-9=9-2x calculate the difference

2x+2x-9= 9 move variable to left side and change sign

2x+2x= 9+9 move constant to right side and change sign

4x= 18 collect like terms

x=9/2 divide both sides by 4

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3 years ago

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$6.83

Step-by-step explanation:

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3 years ago

Can somebody tell me how to do this?

valentinak56 [21]

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3 years ago

If the distance from A (5,6) to B (1, b) is twice the distance from B to

Nimfa-mama [501]

Answer:

The possible values of $b$ are -2.944 and -9.055, respectively.

Step-by-step explanation:

From statement we know that $AB = 2\cdot BC$ . By Analytical Geometry, we use the equation of a line segment, which is an application of the Pythagorean Theorem:

$AB = 2\cdot BC$

$\sqrt{(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2}} = 2\cdot \sqrt{(x_{C}-x_{B})^{2}+(y_{C}-y_{B})^{2}}$ (1)

Where:

$x_{A}$ , $x_{B}$ , $x_{C}$ - x-Coordinates of points A, B and C.

$y_{A}, y_{B}, y_{C}$ - y-Coordinates of points A, B and C.

$(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2} = 4\cdot (x_{C}-x_{B})^{2}+4\cdot (y_{C}-y_{B})^{2}$

Then, we expand and simplify the expression above:

$x_{B}^{2}-2\cdot x_{A}\cdot x_{B} +x_{A}^{2} +y_{B}^{2}-2\cdot y_{A}\cdot y_{B} + y_{A}^{2} = 4\cdot (x_{C}^{2}-2\cdot x_{C}\cdot x_{B}+x_{B}^{2})+4\cdot (y_{C}^{2}-2\cdot y_{C}\cdot y_{B}+y_{B}^{2})$

$x_{B}^{2}-2\cdot x_{A}\cdot x_{B} + x_{A}^{2} +y_{B}^{2}-2\cdot y_{A}\cdot y_{B} + y_{A}^{2} = 4\cdot x_{A}^{2}-8\cdot x_{C}\cdot x_{B}+4\cdot x_{B}^{2}+4\cdot y_{C}^{2}-8\cdot y_{C}\cdot y_{B}+4\cdot y_{B}^{2}$

If we know that $x_{A} = 5$ , $y_{A} = 6$ , $x_{B} = 1$ , $y_{B} = b$ , $x_{C} = 1$ and $y_{C} = -3$ , then we have the following expression:

$1 -10 +25 +b^{2} -12\cdot b+36 = 100 -8 +4 +36+24\cdot b +4\cdot b^{2}$

$b^{2}-12\cdot b +52 = 4\cdot b^{2}+24\cdot b +132$

$3\cdot b^{2}+36\cdot b +80 = 0$

This is a second order polynomial, which means the existence of two possible real solutions. By Quadratic Formula, we have the following y-coordinates for point B:

$b_{1} \approx -2.944$ , $b_{2} \approx -9.055$

In consequence, the possible values of $b$ are -2.944 and -9.055, respectively.

8 0

3 years ago

Solve the for the variable. SHOW ALL WORK/EXPLAIN EVERY STEP!!!2(x-2)-5=3-2x+6​

Solve the for the variable. SHOW ALL WORK/EXPLAIN EVERY STEP!!!2(x-2)-5=3-2x+6