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3 years ago

10

Find the mean and standard deviation of the data. Round to the nearest tenth. 542, 150, 134, 101, 757, 262, 303, 825, 957, 290,

793, 221

1 answer:

kotegsom [21]3 years ago

4 0

Mean is 444.6
Standard deviation is 311.1

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Help me??? lol i dont get this

Anon25 [30]

Answer: 200 in squared

Step-by-step explanation:

Each of the triangles in this picture are the same. You can tell because it's a square, and because of the dotted line.

Take the white triangle and substitute it for one of the black ones. Now, you have this.

Now, just do 10 * 20

= 200

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3 years ago

A twown in east Texas got 10 inches of rain in a week depending on temperatures humidity and time of the year at this rate how t

Aleonysh [2.5K]

10 inches...................7 days
x inches......................24 days
x=24*10/7=240/7≈34,28 inches

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3 years ago

For number 42 what's the equation b.h/2 ? What do we do for x

sergij07 [2.7K]

Notice the picture below

thus, we know the total area is 70 square meters
now, if we add those areas, it should give us 70
thus

(5x)+(40)+(5x)=70 solve for "x"

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3 years ago

An art museum has a pentagon-shaped room. When drawn to scale on a coordinate grid, the corners of the room are points (18,20):

AURORKA [14]

Answer:

$2\ gal$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$A(18,20),B(4,20),C(4,4),D(16.2),E(22.10)$

step 1

Find the distance AB

we have

$A(18,20),B(4,20)$

substitute in the formula

$d=\sqrt{(20-20)^{2}+(4-18)^{2}}$

$d=\sqrt{(0)^{2}+(-14)^{2}}$

$AB=14\ ft$

step 2

Find the distance BC

we have

$B(4,20),C(4,4)$

substitute in the formula

$d=\sqrt{(4-20)^{2}+(4-4)^{2}}$

$d=\sqrt{(-16)^{2}+(0)^{2}}$

$BC=16\ ft$

step 3

Find the distance DE

we have

$D(16.2),E(22.10)$

substitute in the formula

$d=\sqrt{(10-2)^{2}+(22-16)^{2}}$

$d=\sqrt{(8)^{2}+(6)^{2}}$

$d=\sqrt{100}$

$DE=10\ ft$

step 4

Find the distance AE

we have

$A(18,20),E(22.10)$

substitute in the formula

$d=\sqrt{(10-20)^{2}+(22-18)^{2}}$

$d=\sqrt{(-10)^{2}+(4)^{2}}$

$d=\sqrt{116}$

$AE=10.77\ ft$

step 5

Find out the area of the four walls

To determine the area sum the length sides and multiply by the height of the walls

so

$A=(AB+BC+DE+AE)h$

substitute the given values

The height of the walls is 10 ft

$A=(14+16+10+10.77)10$

$A=(50.77)10$

$A=507.7\ ft^2$

step 6

Determine the number of gallons needed to paint the four walls

we know that

one gallon of paint is enough to cover 400 square feet

using proportion

$\frac{1}{400}\ \frac{gal}{ft^2}=\frac{x}{507.7}\ \frac{gal}{ft^2}\\\\x=507.7/400\\\\x= 1.27\ gal$

Round up

$x=2\ gal$

5 0

3 years ago

Which equation can you use to solve for x? x + 56 = 180 x + 146 = 180 180−x=146 x + 56 = 146 The figure contains a pair intersec

Harlamova29_29 [7]

The correct question is
<span>Which equation can you use to solve for x? x + 56 = 180 x + 146 = 180 180−x=146 x + 56 = 146 The figure contains a pair intersecting lines. One of the four angles formed by the intersecting lines is labeled 146 degrees. The angle opposite and not adjacent to this angle is broken into two smaller angles by a ray that extends from the point where the two lines intersect. One of these smaller angles is labeled 56 degrees, and the other smaller angle is labeled x degrees.

see the picture attached to better understand the problem

we know that
angle 146</span>° and angle (56°+x°) area equal -----> by vertical angles
so
146=56+x
therefore

the answer is
<span>x + 56 = 146</span>

3 0

3 years ago