Can I have a macpizzachicken

Write the standard form of the line that passes through the given points.

serious [3.7K]

First of all, remember what the equation of a line is:

y = mx+b

First, let's find what m:
m = 1-(-3) / 2-(-1)
m = 4/3

so: y = 4/3x + b

Now, what about b, or the y-intercept?

To find b, think about what your (x,y) points mean:
(-1,-3).
When x of the line is -1, y of the line must be -3.
(2,1).
When x of the line is 2, y of the line must be 1.

Now, look at our line's equation so far: y=4/3x+b.

You can plug either (x,y) point you want into the x and y variables..the answer will be the same:
(-1,-3)
-3=4/3 × -1+b,
b=-3-(4/3)(-1)
b=-5/3

(2,1)
1=4/3 × 2+b
b=1-(4/3)(2).
b=-5/3.
In both cases we got the same value for b.

So we have y = 4/3x -(5/3).

In standard form it would be:
(4/3)x - y = (5/3)

6 0

3 years ago

Factor the expression x-x^2y^2

ivann1987 [24]

Factor the expression x-x^2y

5 0

3 years ago

How is the 7 in 2,054,867,372, in the thousands column

stellarik [79]

Because it's the first number in front of three numbers. eg. 2659. Any number (in this case the number 2)in front of the three numbers (659)is always in the thousands column.

5 0

4 years ago

HELP, WILL MARK BRAINLIEST+100 POINTS. PLEEEEES Square EFGH is drawn on a coordinate plane. Diagonal FH is on the line y − 3 = n

vova2212 [387]

1) Slope of diagonal GE: 3

2) Equation of the line: $x-y=P-Q$

3) Slope of the line: 1

4) y-intercept: 4

Step-by-step explanation:

1)

Here the diagonal FH is given by the line with equation

$y-3=-\frac{1}{3}(x+9)$

This line is written in the form

$y-y_0 = m(x-x_0)$

where m is the slope of the line and $(x_0,y_0)$ are the coordinates of a point on the line.

Therefore, for line FH we have:

$m=-\frac{1}{3}$ (slope)

$(x_0,y_0)=(-9,3)$

Diagonal GE is perpendicular to diagonal FH (the diagonals in a square are perpendicular): this means that its slope must be equal to the inverse reciprocal of the slope of FH. THerefore, the slope of diagonal GE is

$m_{GE}=-\frac{1}{m_{FH}}=-\frac{1}{-1/3}=3$

2)

Two lines are said to be parallel when they have same slope.

Here, we see that the line given in the plot passes through the points

$(x_1,y_1)=(0,5)\\(x_2,y_2)=(-3,2)$

Therefore the slope of the line shown is

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{5-2}{0-(-3)}=1$

This means that also the line that we want to find must have slope of 1:

$m=1$

Now we can use the following form to write the equation of this line:

$y-y_0 = m(x-x_0)$

where:

$m=1$

$(x_0, y_0)=(P,Q)$ is the point that must be on the line

Therefore,

$y-Q=1(x-P)\\y-Q=x-P\\x-y=P-Q$

3)

In order to solve this problem, we have to find the slope of the side WV.

The coordinates of the two points are:

$V(a+5,b-1)\\W(a+3,b-3)$

Therefore, the slope of side WV is given by:

$m=\frac{y_W-y_V}{x_W-x_V}=\frac{(b-3)-(b-1)}{(a+3)-(a+5)}=\frac{-2}{-2}=1$

And we said that two lines are parallel if they have same slope: therefore, the slope of the line parallel to the line that contains side VW is also 1.

4)

The line given in this problem has equation:

$y=\frac{4}{3}x+1$