Step-by-step explanation:
Given,
length of rectangle(l)= 8cm
area of rectangle(A) = 48cm2
breadth of rectangle(b) = ?
Perimeter of rectangle (P)=?
We know ,
Area of rectangle(A) = l×b
or, 48cm2 = 8cm×b
or, 48cm2 = 8bcm
or, 48cm2/8cm = b
or, 6cm = b
or, b = 6cm
therefore, b = 6cm
Perimeter of rectangle (P) = 2(l+b)
= 2(8cm+6cm)
= 2×14cm
= 28cm
therefore, Perimeter of rectangle(P) = 28cm
Now,
According to the question,
Perimeter of rectangle(P) = Perimeter of square(P)
So,
Perimeter of square(P) = 28cm
length of square(l) = ?
Area of square (A) = ?
We know,
Perimeter of square (P) = 4l
or, 28cm = 4l
or, 28cm/4 = l
or, 7cm = l
or, l = 7cm
therefore, l = 7cm
Now,
Area of square (A) = l^2
= (7cm)^2
= 7cm×7cm
= 49cm^2
therefore, area of square (A)= 49cm^2
43. 125 milliliters
45. 9 tsp
49. 6 tsp
The value of this equation is: 4
Answer: 4
Answer:
The points for the given to linear equations is (5 , - 2) and (5 , - 1)
The points is plotted on the graph shown .
Step-by-step explanation:
Given as :
The two linear equation are
y =
x - 1 ...........1
y =
x - 6 ...........2
Now, Solving both the linear equations
Put the value of y from eq 2 into eq 1
I.e
x - 6 =
x - 1
Or,
x +
x = 6 - 1
Or,
x = 5
or,
x = 5
∴ x = 5
Now, Put the value of x in eq 1
So, y =
x - 1
Or, y =
× 5 - 1
or, y =
- 1
Or, y = - 1 - 1
I.e y = -2
So, For x = 5 , y = - 2
Point is (
,
) = (5 , - 2)
Again , put the value of x in eq 2
So, y =
x - 6
Or, y =
× 5 - 6
Or, y =
- 6
Or, y = 4 - 6
I.e y = - 2
So, For x = 5 , y = - 2
Point is (
,
) = (5 , - 2)
Hence, The points for the given to linear equations is (5 , - 2) and (5 , - 2)
The points is plotted on the graph shown . Answer