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Bogdan [553]
3 years ago
15

In pea plants, smooth (S) peas are dominant over wrinkled (s) peas in the single gene controlling pea texture. A plant with smoo

th peas is crossed with a plant with wrinkled peas. Of the progeny, 252 are smooth and 247 are wrinkled. What are the genotypes of the parent plants?
Biology
1 answer:
OlgaM077 [116]3 years ago
3 0

Answer:

Ss and ss

Explanation:

<em>Since the smooth trait (S) is dominant over the wrinkle trait (s), the genotype of the wrinkled pea parent is definitely </em><em>ss</em><em>.</em>

<em>Also, some of the progeny had wrinkled pea texture (ss). Each of the 2 wrinkled alleles must have been donated by each of the parent. It thus means that the smooth pea parent is heterozygous for the trait (</em><em>Ss</em><em>).</em>

Now, let us look at a cross between the two parents;

  Ss   x   ss

Progeny: Ss, Ss, ss, ss.

Phenotypically, 50% of the progeny are smooth peas while 50% are wrinkled.

Looking at the population of each of the phenotype resulting from the cross. 252:247 is approximately a 50:50 ratio.

Hence, the genotypes of the two parents are Ss and ss.

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3 years ago
A planet has a mass of 5.97 x 1024 kg and a radius of 6.38 x 106 m. Find the weight of a 65.0 kg person at 1000 km above the sur
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To calculate the weight of a person, we use the formula:

w=mg     ....(1)

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For the calculation of weight, we need to first find the acceleration due to gravity and for that we use the formula:

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Putting values in above equation, we get:

g=\frac{(6.67\times 10^{-11}kgm/s^2.m^2/kg^2)(5.97\times 10^{24}kg)}{(6.38\times 10^6m)^2}\\\\g=9.782m/s^2

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w=65kg\times 9.782m/s^2=635.83N

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