The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
He should use yards or meters
Answer: Marked Prixe = Rs. 1800
Step-by-step explanation:
Let the marked price be M
1) A retailer allowed 12% discount and sold a T-shirt at a loss of Rs 16.
SP = 0.88M
CP - SP = 16
CP = 16 + SP
CP = 16 + 0.88M
2) If he had sold it at 10% discount he would have gained Rs 20.
SP = 0.9M
SP - CP = 20
0.9M = 20 + CP
CP = 0.9M - 20
16 + 0.88M = 0.9M - 20
0.9M - 0.88M = 20+16
0.02M = 36
36 = 0.02M
M = 1800
