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Alchen [17]
3 years ago
12

HELPㅔPLS! BOTS STAY AWAY!! The mean amount of money withdrawn from

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
8 0
45$ because of 120$ and 80$
FromTheMoon [43]3 years ago
6 0
The answer is $45 it wasn’t that hard

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**DUE AT 2:15 P.M, NEED ANSWER NOW
Natalka [10]

Answer:

You should guess

Step-by-step explanation:

If you have good luck you will get it right

8 0
2 years ago
As the temperature increases what happens to ice cream sales ?
GalinKa [24]

Answer:

As the temperature rises the sales increase

Step-by-step explanation:

5 0
3 years ago
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√108<br><img src="https://tex.z-dn.net/?f=9%20%5Ctimes%20%5Cfrac%7B13%7D%7B20%7D%20" id="TexFormula1" title="9 \times \frac{13}{
ki77a [65]
I'm assuming your allowed to use a calculator for this? That's what I would do.
\sqrt{108}  = 10.39
To go about the fraction, take the whole number and times it by the denominator, then add in the numerator to create a new fraction(a whole one not mixed). Then simply divide the numerator by the denominator.
9 \times 20 = 180
180 + 13 = 193
193 is the new numerator and the new whole fraction is this and dividing it out gives you,
\frac{193}{20}  = 9.65
For the third one, just input it into a calculator,
2\pi + 3.4 = 9.68
4 0
3 years ago
Type the correct answer in each box. Round numbers to the nearest tenth, if necessary.
nexus9112 [7]

ANSWER

x = 1.6

EXPLANATION

The given equation is:

- 0.5x - 2 = 2x - 1 - 6

Group similar terms to obtain:

- 0.5x - 2x =  - 5 - 1 + 2

Simplify similar terms,

- 2.5x =  - 4

Divide both sides by -2.5

x =  \frac{ - 4}{ - 2.5}

x = 1.6

3 0
3 years ago
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What is the mathematical relationship between the atomic radius (r) and the lattice parameter (a0) in the BCC structure? a. b. c
ryzh [129]

Answer: Lattice parameter, a = (4R)/(√3)

Step-by-step explanation:

The typical arrangement of atoms in a unit cell of BCC is shown in the first attachment.

The second attachment shows how to obtain the value of the diagonal of the base of the unit cell.

If the diagonal of the base of the unit cell = x

(a^2) + (a^2) = (x^2)

x = a(√2)

Then, diagonal across the unit cell (a cube) makes a right angled triangle with one side of the unit cell & the diagonal on the base of the unit cell.

Let the diagonal across the cube be y

Pythagoras theorem,

(a^2) + ((a(√2))^2) = (y^2)

(a^2) + 2(a^2) = (y^2) = 3(a^2)

y = a√3

But the diagonal through the cube = 4R (evident from the image in the first attachment)

y = 4R = a√3

a = (4R)/(√3)

QED!!!

8 0
3 years ago
Read 2 more answers
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