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bixtya [17]
2 years ago
5

Which expression is equivalent to(60)^2-(12)^2?

Mathematics
2 answers:
solmaris [256]2 years ago
4 0

Answer:

the answer is b

Step-by-step explanation:

(60-12)(60-12)

seraphim [82]2 years ago
3 0

Answer:

The answer is

{60}^{2}  -  {12}^{2}  \\  = (60 - 12)(60 + 12)

Step-by-step explanation:

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(2t^(3)+3t-4)-(4t^(2)-6t)
Gnoma [55]

2

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2

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9

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Step-by-step explanation:

3 0
3 years ago
A right triangle has a side of length 1 fourth and a hypotenuse of length 1 third. What is the length of the other side?
Marina86 [1]

Answer:

The other side = \frac{1}{12} units

Step-by-step explanation:

A right triangle has a side of length \frac{1}{4} units and;

the hypotenuse is \frac{1}{3}

According to Pythagorean theorem,

a² + b² = c² , where a and b are the two legs of a triangle and c is the hypotenuse.

Lets say a² = (\frac{1}{4}) ^2   and  c² = ((\frac{1}{3} )^2

b² = c² - a²

b² = \frac{1}{9} - \frac{1}{16} = \frac{1}{144}

So b = \sqrt{1/144} = \frac{1}{12} units.

So the other side = \frac{1}{12} units.

5 0
3 years ago
Mark makes three pounds of hamburger to feed his family of 6. How many pounds of hamburger should you purchase for Memorial Day
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Read 2 more answers
Determine (without solving the problem) an interval in which the solution of the given initial value problem is certain to exist
yuradex [85]

Answer:

0 < t < 5 is the required interval for the differential equation (t - 5)y' + (ln t)y = 6t to have a solution.

Step-by-step explanation:

Given the differential equation

(t - 5)y' + (ln t)y = 6t

and the condition y(1) = 6

We can rewrite the differential equation by dividing it by (t - 5) as

y' + [(ln t)/(t - 5)]y = 6t/(t - 5)

(ln t)/(t - 5) is continuous on the interval (0, 5) and (5, +infinity).

6t/(t - 5) is continuous on (-infinity, 5) and (5, +infinity)

We see that for these expressions, we have continuity at the intervals (0, 5) and (5, +infinity).

But the initial condition is y = 6, when t = 1.

The solution to differential equation is certain to exist at (0, 5)

Which implies that

0 < t < 5

is the required interval.

3 0
3 years ago
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