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3 years ago

What is 31; can vary by 7% ?

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

5 0

9514 1404 393

Answer:

28.83 ≤ x ≤ 33.17

Step-by-step explanation:

7% of 31 is ...

0.07 × 31 = 2.17

When we say the value can vary from 31 by 7%, we usually mean it can go that much lower or higher. For some value x, this means ...

31 -2.17 ≤ x ≤ 31 +2.17

28.83 ≤ x ≤ 33.17

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Step-by-step explanation:

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3 years ago

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4 years ago

from the edge of a 486-foot cliff, peyton shot an arrow over the ocean with an initial upward velocity of 90-feet per second

anygoal [31]

Answer:

9 seconds

Step-by-step explanation:

The complete question is

The altitude of an object, d, can be modeled using the equation below:

d=-16t^2 +vt+h

from the edge of a 486 foot cliff, Peyton shot an arrow over the ocean with an initial upward velocity of 90 feet per second. In how many seconds will the arrow reach the water below?

Let

d ----> the altitude of an object in feet

t ---> the time in seconds

v ---> initial velocity in ft per second

h ---> initial height of an object in feet

we have

$d=-16t^2 +vt+h$

we know that

When the arrow reach the water the value of d is equal to zero

we have

$v=90\ ft/sec$

$h=486\ ft$

$d=0\ ft$

substitute the values and solve for t

$0=-16t^2 +(90)t+486$

$-16t^2+90t+486=0$

Multiply by -1 both sides

$16t^2-90t-486=0$

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$a=16\\b=-90\\c=-486$

substitute in the formula

$t=\frac{90(+/-)\sqrt{-90^{2}-4(16)(-486)}}{2(16)}$

$t=\frac{90(+/-)\sqrt{39,204}}{32}$

$t=\frac{90(+/-)198}{32}$

$t_1=\frac{90(+)198}{32}=9\ sec$

$t_2=\frac{90(-)198}{32}=-3.375\ sec$

the solution is t=9 sec

see the attached figure to better understand the problem

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3 years ago

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3 years ago

The ordered pairs (1, 1), (2, 8), (3, 27), (4, 64), and (5, 125) represent a function. What is a rule that represents this funct

Aleonysh [2.5K]

Hmm

2 times 4=8
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1 times 1=1
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aka
1 times 1^2=1
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the rule is y=x^3

3 0

3 years ago

Read 2 more answers