Sqr root of 5= 2.2360679775
If (3x+2)(x+4) = 0 then one of the 2 factors ( or both) have to be 0. set each to ,0 and solve for x
3x+2=0 means x =-2/3
if x,+4=0 then x = -4
that's your two zeros
Lemme try k
(x-3)(x+2)
=x^2-3x+2x-6
x^-x-6
x^2-x-30 = 0
(x-6)(x+5) = 0
x-6 =0
x=6
x+5 =0
x=-5
x=6 or x=-5
great I failed
Answer:
72
Step-by-step explanation:
IT'S meep 4x – 10 = x2 – 5x + 10 ( y = 4x - 10 is substitute for y).................
PROOF: y + 5x = x²<span> + 10
</span> (4x - 10) + 5x = x² + 10
4x - 10 = x² -5x + 10
<span>
</span>0 = x2 – 9x + 20<span> (liked terms are grouped and simplified)....
PROOF: </span> 4x - 10 = x² -5x + 10
4x = x² -5x + 10 + 10
0 = x² -5x -4x + 20
0 = x² - 9x + 20
Solving:
x² - 9x + 20 = 0
x² - 5x - 4x + 20 = 0
(x - 5) (x - 4) = 0
⇒ x = 4 (as question says) OR x = 5......