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emmasim [6.3K]
3 years ago
6

An architecture student measured the heights of all the buildings downtown.

Mathematics
1 answer:
NeX [460]3 years ago
3 0
I don’t get it ?????
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Josh estimates the height of his desk. what is the reasonable estimate?…
Ugo [173]
I cant answer if there is no info
5 0
3 years ago
Divide. 2/7 divided by 1/3
Allushta [10]

Answer:

The answer to the question provided is \frac{6}{7}.

7 0
3 years ago
What’s the distance between the points (-11, -16) and (20, -16)
pishuonlain [190]

Answer:

Sorry no one has answered for so long, by now you probably already answered but anyway, the answer would be 31.

Step-by-step explanation:

Because the y axes values are the same, we just need to figure out how far they are on the x axes. Which is indeed 31.

5 0
3 years ago
Suppose a classroom teacher wants to measure whether offering candy as a reward will increase the number of times that a student
ahrayia [7]

Answer:

C) Matched pairs

Step-by-step explanation:

Matched samples (also called matched pairs, paired samples or dependent samples) is a type of sampling that involves pairing participants that share every characteristic except for the one under study. The paired participants could be same individuals studied at different time such as:

  1. The study of same participants before and after an interference.
  2. The study of the same participants at two different interference.
5 0
3 years ago
Which of these limits evaluate to 0?
Vikentia [17]
<h3>Answer: C) I and II only</h3>

===============================================

Work Shown:

Part I

\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\

----------

Part II

\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\

----------

Part III

\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\

7 0
2 years ago
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