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schepotkina [342]
3 years ago
6

The stopping distance of a car is modeled by the function d = 0.05r(r + 2) where d is the stopping distance of the car measured

in feet and r is the speed of the car in miles per hour. If skid marks left on the road are 75 feet long, how fast was the car traveling?
Mathematics
1 answer:
adell [148]3 years ago
3 0

Answer:

The car was moving approximately at a speed of 37.74 miles per hour.

Step-by-step explanation:

We are given the following in the question:

The stopping distance of a car is given by

d = 0.05r(r + 2)

where d is the stopping distance in feet and r is speed of the car in miles per hour.

The stopping distance is 75 feet, we have to find the speed of the car,

Putting d = 75 in the equation, we get,

75 = 0.05r(r + 2)\\r^2 + 2r = 1500\\r^2 + 2r-1500 = 0\\\\r =\dfrac{-2\pm \sqrt{4-(4)(1)(-1500)}}{2}\\\\r\approx -39.74,37.74

Thus, the car was moving approximately at a speed of 37.74 miles per hour.

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Volume of a Sphere = 4/3 πr³
v = 4/3 * 3.14 * 12³
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Difference = 24,416.64 - 7234.56 = 17182.08

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Hope this helps!
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Step-by-step explanation:

1) ?

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You're making this really tough on me.. I can just barely read the equations

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that worked out well :

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