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yarga [219]
3 years ago
10

The width of a rectangle is "w" inches long. If the length is 4

Mathematics
1 answer:
umka2103 [35]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Area of rectangle=length(l)×width(w)

In this case,length= w+4

so Area=(w+4)×w

Therefore Area=w^2+4w

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Will give brainliest-H(t)=-16t^2+28t
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3 years ago
For the data set below, which of the following are true? {12, 18, 28, 14, 18, 20, 12}
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Read 2 more answers
Express p in terms of q if
Irina-Kira [14]

p=x^2+\dfrac{1}{x^2}\\\\p=\dfrac{x^4}{x^2}+\dfrac{1}{x^2}\\\\p=\dfrac{x^4+1}{x^2}\qquad(*)

q=x+\dfrac{1}{x}\\\\q=\dfrac{x^2}{x}+\dfrac{1}{x}\\\\q=\dfrac{x^2+1}{x}\qquad\text{square both sides}\\\\q^2=\left(\dfrac{x^2+1}{x}\right)^2\\\\q^2=\dfrac{(x^2+1)^2}{x^2}\qquad\text{use}\ \ (a+b)^2=a^2+2ab+b^2\\\\q^2=\dfrac{(x^2)^2+2(x^2)(1)+1^2}{x^2}\\\\q^2=\dfrac{x^4+2x^2+1}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+\dfrac{2x^2}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+2\qquad\text{subtract 2 from both sides}\\\\q^2-2=\dfrac{x^4+1}{x^2}\\\\\text{From (*) we have}\\\\\boxed{p=q^2-2}

8 0
3 years ago
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