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Novosadov [1.4K]
3 years ago
10

(b) The perimeter of a rectangular window is 298 cm.

Mathematics
1 answer:
Ronch [10]3 years ago
3 0

Answer:

68

Step-by-step explanation:

81 +81 is 162

298-162=136

136/2=68

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Answer:

150n is answer odd this q

8 0
3 years ago
1. Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary.
gtnhenbr [62]
1. First, we are going to draw our triangle (picture 1). Next, we are going to use the cosine rule to find the length of side b:
b^2=a^2+c^2-2accosA
b= \sqrt{a^2+c^2-2accosA}
b= \sqrt{14^2+20^2-2(14)(20)cos(74)}
b=21.02
Now that we have all the sides of the triangle, we use Heron's formula to find its area. But first we need to find the semi-perimeter of the triangle. To do it, we are going to use the formula: s= \frac{a+b+c}{2}
where 
s is the semi-perimeter.
a, b, and c are the sides of the triangle. 

s= \frac{14+21.02+20}{2}
s= \frac{54.02}{2}
s=27.51

Now, we can use Heron's formula: A= \sqrt{s(s-a)(s-b)(s-c)}
where
A is the area of the triangle.
s is the semi-perimeter of the triangle.
a, b, and c are the sides of the triangle.
A= \sqrt{27.51(27.51-14)(27.51-21.02)(27.51-20}
A=134.59cm^2

The area of the triangle ABC is 134.59 square centimeters. We can conclude that the correct answer of your given choices is: 134.58 cm2 (your teacher made a little rounding error)

2. Just like before, the first thing we are going to do is draw the triangle (picture 2). Next, we are going to use the cosine rule to find the length of side b:
b= \sqrt{a^2+c^2-2accosA}
b= \sqrt{11^2+18^2-2(11)(18)cos(71)}
b=17.78

Semi-perimeter:
s= \frac{a+b+c}{2}
s= \frac{11+17.78+18}{2}
s=23.39

Heron's formula:
A= \sqrt{s(s-a)(s-b)(s-c)}
A= \sqrt{23.39(23.39-11)(23.39-17.78)(23.39-18)}
A=93.61cm^2

The area of triangle ABC is 93.61 square centimeters. We can conclude that the correct answer is <span>93.61 cm2

3. We have the vectors </span><span>P = (-5, 5) and Q = (-13, 6), and we want to find the vector 2 times PQ; in other words, we want to find the result of the multiplication between the vector initiating at P and ending at Q and the scalar 2.
First we are going to find the components of the vector </span>P and ending at Q:
PQ=\ \textless \ -13-(-5), 6-5\ \textgreater \
PQ=\ \textless \ -13+5, 1\ \textgreater \
PQ=\ \textless \ -8,1\ \textgreater \

Next, we are going to multiply the vector by the scalar 2:
2PQ=2\ \textless \ -8,1\ \textgreater \
2PQ=\ \textless \ -16,2\ \textgreater \

Now, we can find the magnitude of the vector. Remember that the magnitude of a vector is given by the Pythagorean theorem: |a|= \sqrt{x^2+y^2}
where
|a| is the magnitude of the vector 
\ \textless \ x,y\ \textgreater \ are the components of the vector.

We know that the components of the vector are x=-16 and y=2, so lets replace those vales in our equation: 
|2PQ|= \sqrt{-16^2+2^2}
|2PQ|= \sqrt{-16^2+2^2}
|2PQ|= \sqrt{256+4}
|2PQ|= \sqrt{260}

We can conclude that the correct answer is: <span><-16, 2>, square root of two hundred and sixty.</span><span>
</span>

4 0
4 years ago
What is the general form of the equation of the line shown?
Nostrana [21]

Hey There!

The formula of the general form equation is

0 = Ax + By + C

As we look at the answer choices we see that the last choice best represents the correct answer.

x + y + 2 = 0

Best matches the formula given and therefore that would be the correct answer.

Thus, the answer would be x + y + 2 = 0

Thank you for posting your question with Brainly!

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3 years ago
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5 cups
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A 70-ft ladder is mounted 10 ft above the ground on a fire truck. The bottom of the ladder is 40
riadik2000 [5.3K]

\text{Hello there!}\\\\\text{Use the Pythagorean theorem first:}\\\\a^2+b^2=c^2\\\\\text{Plug 70 to c since it's your hypotenuse and plug 40 to a}\\\\40^2+b^2=70^2\\\\\text{Solve for b:}\\\\40^2+b^2=70^2\\\\1600+b^2=4900\\\\\text{Subtract 1600 from both sides}\\\\b^2=3300\\\\\text{Square root}\\\\b=57.4456\\\\\text{Round to the nearest tenth}\\\\57.4\\\\\text{Add 10 to 55.4 because the ladder is 10 ft off the ground}\\\\67.4\\\\\boxed{\text{Answer: about 67.4 ft}}

3 0
3 years ago
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