All categories

3 years ago

24 X 2 + 2 please help

Mathematics

1 answer:

Vinil7 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

24x2=48

48+2=50

You might be interested in

Kathryn deposits 100 into an account at the beggining of each 4 year period for 40 years. The account credits interest at an eff

OleMash [197]

Answer:

6194.84

Step-by-step explanation:

Using the formula for calculating accumulated annuity amount

F = P × ([1 + I]^N - 1 )/I

Where P is the payment amount. I is equal to the interest (discount) rate and N number of duration

For 40 years,

X = 100[(1 + i)^40 + (1 + i)^36 + · · ·+ (1 + i)^4]

=[100 × (1+i)^4 × (1 - (1 + i)^40]/1 − (1 + i)^4

For 20 years,

Y = A(20) = 100[(1+i)^20+(1+i)^16+· · ·+(1+i)^4]

Using X = 5Y (5 times the accumulated amount in the account at the ned of 20 years) and using a difference of squares on the left side gives

1 + (1 + i)^20 = 5

so (1 + i)^20 = 4

so (1 + i)^4 = 4^0.2 = 1.319508

Hence X = [100 × (1 + i)^4 × (1 − (1 + i)^40)] / 1 − (1 + i)^4

= [100×1.3195×(1−4^2)] / 1−1.3195

X = 6194.84

4 0

3 years ago

Read 2 more answers

Pls help pls pls pls

VLD [36.1K]

Answer:

Step-by-step explanation:

7 0

2 years ago

Evaluate [3(5 + 6) + 2] ÷ 7

larisa86 [58]

The answer to the problem is 5

6 0

3 years ago

Read 2 more answers

What is perpendicular to y=-1/2x+11

ratelena [41]

You have to find the reciprocal of the gradient - 1/2
And to do that just flip the sign and fraction:
-1/2
1/2
2/1

So the answer is,
Y = 2x + 11

3 0

3 years ago

Which systems of equations intersect at point A in this graph?

abruzzese [7]

Answer:

The point of intersection of the system of equations is:

(x, y) = (-2, 1)

The correct system of equations intersect at point A in this graph will be:

$\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}$

Thus, the second option is correct.

Step-by-step explanation:

Given the point

A (-2, 1)

Let us check the system of equations to determine whether it intersect at point A in this graph.

Given the system of equations

$\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}$

Arrange equation variable for elimination

$\begin{bmatrix}y-4x=9\\ y+3x=-5\end{bmatrix}$

$y+3x=-5$

$-$

$\underline{y-4x=9}$

$7x=-14$

so the system of equations becomes

$\begin{bmatrix}y-4x=9\\ 7x=-14\end{bmatrix}$

Solve 7x = -14 for x

$7x=-14$

Divide both sides by 7

$\frac{7x}{7}=\frac{-14}{7}$

Simplify

$x = -2$

For y - 4x = 9 plug in x = 2

$y-4\left(-2\right)=9$

$y+4\cdot \:2=9$

$y+8=9$

Subtract 8 from both sides

$y+8-8=9-8$

Simplify

y = 1

Thus, the solution to the system of equations is:

(x, y) = (-2, 1)

From the attached graph, it is also clear that the system of equations intersects at point x = -2, and y = 1.

In other words, the point of intersection of the system of equations is:

(x, y) = (-2, 1)

Therefore, the correct system of equations intersect at point A in this graph will be:

$\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}$

Thus, the second option is correct.

3 0

2 years ago