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dezoksy [38]
3 years ago
12

Please help!!!!!! AAA

Mathematics
2 answers:
Citrus2011 [14]3 years ago
8 0
First answer is the correct answer
JulsSmile [24]3 years ago
7 0

Answer:

D is correct

Step-by-step explanation:

1/12^3

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Pls help and show workings <br> Due ASAP
Tanya [424]

Answer:

ASA angle side angle

Step-by-step explanation:

DE=JH(given)

angle E= angle H (given)

angle D=angle J (given)

4 0
3 years ago
Read 2 more answers
(d) Given that n(§) = 96, n(A) = 50 and n(B) = 60. Find the maximum and minimum values for n(An B).
frez [133]

Step-by-step explanation:

the max. value is when the smaller set (A) is completely contained in the larger set (B).

then n(A n B) is n(A) = 50.

the set intersection between A and B cannot get bigger than that. or A gets bigger ...

after all, the intersection means it is a set of all elements that exist in BOTH sets.

but then there must be other elements besides A and B in the universal set too, because n(universal set) = 96, and n(A u B) would be only 60.

the min. value could be the empty set or 0. but because n(universal set) = 96, and n(A) + n(B) = 110 and larger than 96, it means that there have to be some shared elements. at least 110 - 96 = 14 elements.

in this case there cannot be other elements in the universal set than A and B. and n(universal set) = n(AuB) = 96.

3 0
2 years ago
Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra
bearhunter [10]

Answer:

\frac{dh}{dt}=-\frac{1}{2\pi}cm/min

Step-by-step explanation:

From similar triangles, see diagram in attachment

\frac{r}{4}=\frac{h}{16}


We solve for r to obtain,


r=\frac{h}{4}


The formula for calculating the volume of a cone is

V=\frac{1}{3}\pi r^2h


We substitute the value of r=\frac{h}{4} to obtain,


V=\frac{1}{3}\pi (\frac{h}{4})^2h


This implies that,

V=\frac{1}{48}\pi h^3


We now differentiate both sides with respect to t to get,

\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}


We were given that water is drained out of the tank at a rate of 2cm^3/min


This implies that \frac{dV}{dt}=-2cm^3/min.


Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means h=8cm.


We substitute this values to obtain,


-2=\frac{\pi}{16}(8)^2 \frac{dh}{dt}


\Rightarrow -2=4\pi \frac{dh}{dt}


\Rightarrow -1=2\pi \frac{dh}{dt}


\frac{dh}{dt}=-\frac{1}{2\pi}






3 0
4 years ago
Read 2 more answers
Someone please helppp
almond37 [142]

Answer:

Step-by-step explanation:

More information?

7 0
3 years ago
Segment RSRS is parallel to segment VTVT, and segment RVRV is parallel to segment STST. Which statement about the measure of ∠S∠
hram777 [196]
The options are:
A. measurement of angle S = measurement of angle V
B. measurement of angle S = meansurement of angle R
C. measurement of angle S = 180 degrees - measurement of angle T
<span>D. measurement of angle S = 180 degrees - measurement of angle R

The answer s B. The lines form a parallelogram</span>
7 0
3 years ago
Read 2 more answers
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