Answer:
92.8 km
Step-by-step explanation:
s=d/t
58=d/1.6
58*1.6=d
92.8=d
Answer: 49.85%
Step-by-step explanation:
Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.
i.e.
and 
To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.
i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and
.
i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between
and
. (1)
According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.
i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.
i.e.,The approximate percentage of lightbulb replacement requests numbering between
and
= 49.85%
⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%
Answer:
a. quotient refers to division
28 to 42 means 28/42
We now reduce 28/42 to lowest terms.
28 ÷ 7 = 4
42 ÷ 7 = 6
We now have 4/6.
We now reduce 4/6.
4 ÷ 2 = 2
6 ÷ 2 = 3
Final answer: 2/3
Answer:
5
Step-by-step explanation:
Hopebthis helps it ahowed right for me