Answer:
\[y < = 300\]
Step-by-step explanation:
Let x = number of out-of-state students at the college
Let y = number of in-state students at the college
As per the given problem, the constraints are as follows:
\[x < = 100\] --------- (1)
\[y = 3 * x\] --------- (2)
From the given equations (2), \[ x = y/3 \]
Substituting in (1):
\[y/3 < = 100\]
Or, \[y < = 300\] which is the constraint representing the incoming students.
12 lawns/9 hours = 1.33 lawns per hour
Answer:
50
Step-by-step explanation:
as long as the 50 i did this in 5th grade
The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.
Given mean of 14 years, variance of 25 and sample size is 50.
We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.
μ=14,
σ=
=5
n=50
s orσ =5/
=0.7071.
This is 1 subtracted by the p value of z when X=12.5.
So,
z=X-μ/σ
=12.5-14/0.7071
=-2.12
P value=0.0170
1-0.0170=0.9830
=98.30%
Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.
Learn more about probability at brainly.com/question/24756209
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There is a mistake in question and correct question is as under:
What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?
If all were grandstand tickets, revenue would be 0.65*5716 = 3715.40. It was actually 298.50 less than that. Each bleacher ticket sold drops the revenue by .25, so there were 298.50/.25 = 1194 bleacher tickets sold.