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Dima020 [189]
1 year ago
15

I need help in the last one, i don understand it

Mathematics
1 answer:
Alex787 [66]1 year ago
4 0

Answer:

84 = 7×12

84 = 3×4×7

84 = 2×2×3×7

Step-by-step explanation:

84 = 7 × 12 ( the factors of 12 are 3×4)

so 84 = 3×4×7 ( the factors of 4 are 2×2)

so 84 = 2x2x3x7

I hope it helps you!

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Triangle ABC is congruent to triangle DEF. If DE = 41, EF = 23, DF = 36, and AB = 8x − 7, what is x? Round to the nearest tenth.
Nadya [2.5K]

The side AB is equal to the side DE. Then the value of x is 6.

<h3>What is the triangle?</h3>

A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.

Triangle ABC is congruent to triangle DEF.

If DE = 41, EF = 23, DF = 36, and AB = 8x − 7.

Then the side AB is equal to the side DE.

    AB = DE

8x - 7 = 41

    8x = 48

      x = 6

Then the value of x is 6.

More about the triangle link is given below.

brainly.com/question/25813512

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2 years ago
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Michael writes down 4 different factors of 60
Marizza181 [45]

Answer:

34+(-12) =22

Step-by-step explanation:

because they said that adding numbers but they didn't said that negative Or positive. so i took those numbers

3 0
2 years ago
An n × n matrix B has characteristic polynomial p(λ) = −λ(λ − 3) 3 (λ − 2) 2 (λ + 1). Which of the following statements is false
asambeis [7]

Answer:

Only d) is false.

Step-by-step explanation:

Let p=p(\lambda)=\lambda(\lambda-3)^3 (\lambda-2)^2 (\lambda+1) be the characteristic polynomial of B.

a) We use the rank-nullity theorem. First, note that 0 is an eigenvalue of algebraic multiplicity 1. The null space of B is equal to the eigenspace generated by 0. The dimension of this space is the geometric multiplicity of 0, which can't exceed the algebraic multiplicity. Then Nul(B)≤1. It can't happen that Nul(B)=0, because eigenspaces have positive dimension, therfore Nul(B)=1 and by the rank-nullity theorem, rank(B)=7-nul(B)=6 (B has size 7, see part e)

b) Remember that p(\lambda)=\det(B-\lambda I). 0 is a root of p, so we have that p(0)=\det(B-0 I)=\det B=0.

c) The matrix T must be a nxn matrix so that the product BTB is well defined. Therefore det(T) is defined and by part c) we have that det(BTB)=det(B)det(T)det(B)=0.

d) det(B)=0 by part c) so B is not invertible.

e) The degree of the characteristic polynomial p is equal to the size of the matrix B. Summing the multiplicities of each root, p has degree 7, therefore the size of B is n=7.      

8 0
3 years ago
PLEASE I NEED HELP IF IT'S WRONG I WILL REPORT
Alinara [238K]

Answer:

what do you need help wth ?

Step-by-step explanation:

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What is the value of x ?
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