Answer:
segment AB over segment A double prime B double prime = the square root of 13 over 2 times the square root of 13
Step-by-step explanation:
Triangle ABC has vertices at points A(-3,3), B(1,-3) and C(-3,-3).
1. Reflection over x = 1 maps vertices A, B and C as follows
- A(-3,3)→A'(5,3);
- B(1,-3)→B'(1,3);
- C(-3,-3)→C'(5,-3).
2. Dilation by a scale factor of 2 from the origin has the rule
(x,y)→(2x,2y)
So,
- A'(5,3)→A''(10,6);
- B'(1,3)→B''(2,6);
- C'(5,-3)→C''(10,-6)
See attached diagram for details
Note that
so
Number of tacos sold is 65 and number of burritos sold is 40
<h3><u>Solution:</u></h3>
Given that Aiden sells each taco for $4.75 and each burrito for $7
Let the number of tacos sold be "t" and number of burritos sold be "b"
Given that Aiden sold 25 more tacos than burritos
t = b + 25 ---- eqn 1
Also given that yesterday Aiden made a total of $588.75 in revenue
number of tacos sold x cost of each tacos + number of burritos sold x cost of each burritos = 588.75
4.75t + 7b = 588.75 ----- eqn 2
Substitute eqn 1 in eqn 2
4.75(b + 25) + 7b = 588.75
4.75b + 118.75 + 7b = 588.75
11.75b = 470
b = 40
Substitute b = 40 in eqn 1
t = 40 + 25
t = 65
Thus the number of tacos sold is 65 and number of burritos sold is 40
Answer:
The total cost of producing 91 units of ACME rocket fuel is $3999.99.
Step-by-step explanation:
The Marginal Cost is given by the following function
The total cost function is the integrative of the marginal cost function. So:
In which K, the integrative constant, is the fixed cost. So 
.
1. Find the total cost of producing 91 units of ACME rocket fuel.
This is TC(91).
So
The total cost of producing 91 units of ACME rocket fuel is $3999.99.
1.326 grams of NH3 are required to produce 4.65 g of HF.
Step-by-step explanation:
Balanced chemical reaction is written first to know the number of moles taking part in original reaction.
NH3 +3 F2 ⇒3 HF + NF3
Given:
mass of HF = 4.65
First the number of moles of HF in 4.65 grams is calculated by using the formula:
number of moles (n) = 
atomic mass of HF = 20 grams/mole
putting the values in the above equation number of moles can be found.
n = 
= 0.235 moles of HF are given.
From the equation it can be said that:
1 mole of NH3 reacts to form 3 moles of HF
so, x moles of NH3 would react to form 0.235 moles of HF
= 
3x = 0.235
x = 
x = 0.078 moles of NH3 is required.
The moles are converted to mass by applying the formula:
mass = atomic mass X number of moles (atomic mass of NH3 = 17 grams/mole)
putting the values in the formula
mass = 17 X 0.078
mass = 1.326 grams
Answer:
375,000,000 milliliters of water is in the pool.
Step-by-step explanation:
We know
1 liters = 1000 milliliters
hence to convert liter in to milliliter we have to multiply the liter unit with 1000 to get the milliliter
we have to find value of 375,000 liters in milliliters
to get that we multiply both side by 375,000
1* 375,000 liters = 1000* 375,000 milliliters
thus,
375,000 liters = 375,000,000 milliliters
thus, there is 375,000,000 milliliters of water is in the pool.
