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3 years ago

(-3)(+4)=? Can someone tell me the answer to this?

Mathematics

1 answer:

slava [35]3 years ago

5 0

Answer:

-12, or 1 (see explanation)

Step-by-step explanation:

(-3)(+4)

Is the same as

4 * (-3)

which is

-12

Unless your problem is:

(-3) + 4

Then it is the same as

4 - 3

which is

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Someone please help!

Vlad1618 [11]

Multiply the top equation by 6 and the bottom equation by 7. You will cancel x first by doing this and solve for y. You should get y=-1.
Substitute in y for either original equation.
You should get x=1.
Solution is (1,-1).

7 0

3 years ago

For each of the transformed square root functions, state the transformations and use them to plot the

FrozenT [24]

Step-by-step explanation:

so, if I understand this correctly, the original function (shown in the graph) is

f(x) = sqrt(x)

the following transformations were done going from f(x) to h(x) :

x -> x + 4 as variable term moved the whole curve 4 units to the left. because now a specific functional value is calculated for a smaller x (by 4 units) than for the original f(x). e. g. let's call g(x) = sqrt(x + 4). then g(-4) = f(0). as mentioned, everything moved over to the left by 4 units.

sqrt(x) -> 3×sqrt(x) increased the range of the function (the generated y values) by the factor 3. was the functional result for a x value = 1, then it is now 3 for the same x value.

sqrt(x) -> sqrt(x) - 1 moved the whole curve down by 1 unit.

in summary, the whole original curve was moved 4 units to the left, then stretched upwards by the factor 3, and then that result was moved down by 1 unit.

so, e.g.

h(-4) = 3×f(0) - 1 = -1 point (-4, -1) corresponds to old (0, 0)

h(-3) = 3×f(1) - 1 = 2 point (-3, 2) corresponds to old (1, 1)

h(0) = 3×f(4) - 1 = 5 point (0, 5) corresponds to old (4, 2)

8 0

2 years ago

Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form

Alex787 [66]

Answer:

$y=-\frac{2}{5}x-\frac{1}{5}$

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

m is the slope

b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

$m = -\frac{2}{5}$

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

$y=-\frac{2}{5}x + b$

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-3,1). When x of the line is -3, y of the line must be 1.
(2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: $y=-\frac{2}{5}x + b$ . $b$ is what we want, the - $-\frac{2}{5}$ is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

(-3,1). y = mx + b or $1=-\frac{2}{5} * -3 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(-3)$ . $b = -\frac{1}{5}$ .
(2,-1). y = mx + b or $-1=-\frac{2}{5} * 2 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(2)$ . $b = -\frac{1}{5}$ .