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Setler [38]
3 years ago
5

The price of an item has dropped to $33 today.yesterday it was $110.find the percentage decrease

Mathematics
1 answer:
asambeis [7]3 years ago
3 0

Answer: 110 - 33 equals 77.

Step-by-step explanation:

Dude, just subtract- (if I get this wrong I’m sorry)

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Equilateral triangle ABC has an area of \sqrt{3}√ ​3 ​ ​​ . If the shaded region has an area of \piπK − \sqrt{3}√ ​3 ​ ​​ , what
Liono4ka [1.6K]

Answer:

The value of k = 4/3

Step-by-step explanation:

* Lets explain how to solve the problem

- An equilateral triangle ABC is inscribed in a circle N

- The area of the triangle is √3

- The shaded area is the difference between the area of the circle

  and the area of the equilateral triangle ABC

- The shaded are = k π - √3

- We need to find the value of k

* <u><em>At first lets find the length of the side of the Δ ABC</em></u>

∵ Δ ABC is an equilateral triangle

∴ Its area = √3/4 s² , where s is the length of its sides

∵ The area of the triangle = √3

∴ √3/4 s² = √3

- divide both sides by √3

∴ 1/4 s² = 1

- Multiply both sides by 4

∴ s² = 4 ⇒ take √ for both sides

∴ s = 2

∴ The length of the side of the equilateral triangle is 2

* <u><em>Now lets find the radius of the circle</em></u>

- In the triangle whose vertices are A , B and N the center of the circle

∵ AN and BN are radii

∴ AN = BN = r , where r is the radius of the circle

∵ The sides of the equilateral angles divides the circle into 3 equal

   arcs in measure where each arc has measure 360°/3 = 120°

∵ The measure of the central angle in a circle equal the measure

  of the its subtended arc arc

∵ ∠ANB is an central angle subtended by arc AB

∵ The measure of arc AB is 120°

∴ m∠ANB = 120°

- By using the cosine rule in Δ ANB

∵ AB = 2 , AN = BN = r , m∠ANB = 120°

∴ (2)^{2}=r^{2}+r^{2}-2(r)(r)cos(120)

∴ 4=r^{2}+r^{2}-2(r)(r)(-0.5)

∴ 4=r^{2}+r^{2}-(-r^{2})

∴ 4=r^{2}+r^{2}+r^{2}

∴ 4=3r^{2}

- Divide both sides by 3

∴ r^{2}=\frac{4}{3}

- Take square root for both sides

∴ r = 2/√3

* <u><em>Lets find the value of k</em></u>

∵ Area circle = πr²

∵ r = 2/√3

∴ Area circle = π(2/√3)² = (4/3)π

∵ Area shaded = area circle - area triangle

∵ Area triangle = √3

∴ Area shaded = (4/3) π - √3

∵ Area of the shaded part is π k - √3

- Equate the two expressions

∴ π k - √3 = (4/3) π - √3

∴ k = 4/3

* The value of k = 4/3

7 0
3 years ago
What is the area of this figure? Enter your answer in the box.
ElenaW [278]
Area
=3*2/2+6*1/2+3*6/2+(6+7)*6/2
=54

7 0
3 years ago
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Choose the pair(s) of integers that can be substituted into the equation ax2 - 6x + c = 0 so that it has two real solutions.
Maksim231197 [3]

The options are not provided, but method is stated below

Answer:

Quadratic equation ax2 - 6x + c = 0

options would be given for a and c

  1. substitute a and c
  2. check for Discriminant
  3.  b^2 - 4ac \geq  0
  4. 36 -4ac \geq 0

These conditions will fetch us the result required among the options.

Note : the \geq sign will give us the result for Two real unequal solutions and two real equal solutions.  If we only need Real unequal solutions we only use > sign instead of \geq

4 0
3 years ago
Larry spent 1/2 of his money on a camera and another 1/8 on a radio. the camera cost $120 more than the radio. how much money di
elena-s [515]
Let, his original money = x
It would be: x * 1/2 = 120 
x = 120 * 2
x = 240

In short, Your Answer would be $240

Hope this helps!
7 0
3 years ago
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In triangle ABC below, which trigonometric ratio equals 3/2?
Vlada [557]
The figure is right triangle with base =segment AB = 3 and height = segment AC = 2.

The angle B has tangent, tan (B) = 2 / 3

The angle C, has tangent, tan (C) = 3 / 2

Then, the answer is option C, tan C
5 0
3 years ago
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