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Nana76 [90]
3 years ago
13

1/3 n=4 What does n equal?

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

n=12 is the answer

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(p-3)+(p-7) what is the answer
kykrilka [37]
(p-3)+(p-7)\\\\=p-3+p-7\\\\=(p+p)+(-3-7)\\\\=2p+(-10)\\\\=\boxed{2p-10}
3 0
3 years ago
Use the roster method to write each of the given sets. For some exercises you may need to consult a reference, such as the Inter
castortr0y [4]

Answer:

The empty set \{ \}

Step-by-step explanation:

Roster method is simply listing explicitly all the elements in the set, one by one (writing them between two curly brackets, and separating them through commas).

We want then to list explicitly all the elements in the following set:

The set of natural numbers x that satisfy x+2=1.

So, first we have to figure out which numbers are in that set. The set is made ONLY of those natural numbers x, that when you add 2 to them, you get 1. Clearly no natural number has that property (since the only number that would give us 1 when adding 2 to it, is the number -1, which is NOT a natural number). So there aren't any numbers at all in that set. So if we were to list them, we'd just list nothing inside the set:

\{ \} (which is just the empty set)

4 0
3 years ago
Can someone please please help me out I don’t understand this
MatroZZZ [7]

Answer:

Step-by-step explanation:

5 0
3 years ago
Workers at a certain soda drink factory collected data on the volumes​ (in ounces) of a simple random sample of 1818 cans of the
ohaa [14]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Workers at a certain soda drink factory collected data on the volumes​ (in ounces) of a simple random sample of 18 cans of the soda drink. Those volumes have a mean of 12.19 oz and a standard deviation of 0.14 oz, and they appear to be from a normally distributed population.

If the workers want the filling process to work so that almost all cans have volumes between 12.02 oz and 12.66 ​oz, the range rule of thumb can be used to estimate that the standard deviation should be less than 0.16 oz. Use the sample data to test the claim that the population of volumes has a standard deviation less than 0.16 oz. Use a 0.01 significance level. Complete parts​ (a) through​ (d) below.

a. Identify the null and alternative hypotheses.  

b. Compute the test statistic.

c. Find the p-value.

d. State the conclusion.

Answer:

Null hypotheses = H₀: σ = 0.16  oz

Alternate hypotheses = H₁: σ < 0.16  oz

Critical value = 6.408

Chi-square value = \chi^2 = 13.016

Reject H₀  Since \chi^2 > Critical value

Reject H₀ Since p-value ≤ α

We have significant evidence at given significance level that the population of volumes has a standard deviation of less than 0.16 oz.

Step-by-step explanation:

Set up hypotheses:

The null hypotheses is that the population of volumes has a standard deviation of 0.16 oz

Null hypotheses = H₀: σ = 0.16  oz

The claim to be tested is that the population of volumes has a standard deviation of less than 0.16 oz

Alternate hypotheses = H₁: σ < 0.16  oz

Determine type of test:

Since the alternate hypothesis states that the population of volumes has a standard deviation of less than 0.16 oz, therefore we will use a lower-tailed chi-square test.

Determine the Critical value:

Given level of significance = 0.01

Since it is a lower-tailed test, the areas given in the chi-square table are the areas to the right of the critical value. To get the areas on the left, subtract it from  one, and then look it up

α = 1 - 0.01 = 0.99

degree of freedom = df = n - 1 = 18 - 1 = 17

The critical value from the chi-square table at α = 0.99 and df = 17 is found to be

Critical value = 6.408

Using an online “chi-square p-value calculator”

The left tail p-value for df = 17 and Critical value = 6.408 is found to be

p-value = 0.01

Set up decision rule:

Reject H₀ If  > Critical value

We reject the Null hypothesis If the calculated chi-square value is more than the critical value.

OR

Reject H₀ If p-value ≤ α

Compute the test statistic:

$ \chi^2 = \frac{(n-1) s^2}{\sigma^2} } $

$ \chi^2 = \frac{(18-1) 0.14^2}{0.16^2} } $

\chi^2 = 13.016

Conclusion:

We reject H₀

Since \chi^2 > Critical value

13.016 > 6.408

Also

p-value ≤ α

0.01 ≤ 0.01

We have significant evidence at given significance level that the population of volumes has a standard deviation of less than 0.16 oz.

5 0
3 years ago
An altitude is drawn from the vertex of an isosceles triangle, forming a right angle and two congruent triangles. As a result, t
Alenkinab [10]

Answer:

The triangle's perimeter is 61.77 inches.

Step-by-step explanation:

Since an altitude is drawn from the vertex of an isosceles triangle, forming a right angle and two congruent triangles, and as a result, the altitude cuts the base into two equal segments, and the length of the altitude is 26 inches, and the length of the base is 9 inches, to find the triangle's perimeter the following calculation must be performed:

Isosceles triangle = 2 equal sides

To obtain the value of the sides, the Pythagorean theorem must be applied on the right triangle formed with the altitude.

(9/2) ^ 2 + 26 ^ 2 = X ^ 2

4.5 ^ 2 + 26 ^ 2 = X ^ 2

20.25 + 676 = X ^ 2

√ (20.25 + 676) = X

√696.25 = X

26.38 = X

26.3865 x 2 + 9 = X

52.77 + 9 = X

61.77 = X

Therefore, the triangle's perimeter is 61.77 inches.

5 0
2 years ago
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