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saveliy_v [14]
3 years ago
12

Devin runs a factory that makes Blu-ray players. Each R80 takes 9 ounces of plastic and 2 ounces of metal. Each G150 requires 3

ounces of plastic and 6 ounces of metal. The factory has 270 ounces of plastic, 348 ounces of metal available, with a maximum of 18 R80 that can be built each week. If each R80 generates $8 in profit, and each G150 generates $9, how many of each of the Blu-ray players should Devin have the factory make each week to make the most profit?
R80:

G150:

Best profit:

Mathematics
1 answer:
alexira [117]3 years ago
5 0

9514 1404 393

Answer:

  R80: 12

  G150: 54

  Best Profit: $582

Step-by-step explanation:

Let x and y represent the numbers of R80 and G150 players, respectively. The constraints of the problem are ...

  0 ≤ x ≤ 18 . . . . . a maximum of 18 R80 can be built

  0 ≤ y . . . . . . . . . only non-negative numbers can be built

  9x +3y ≤ 270 . . . . ounces of plastic used cannot exceed 270

  2x +6y ≤ 348 . . . . ounces of metal used cannot exceed 348

The objective is to maximize the profit function ...

  P(x, y) = 8x +9y

The attached graph shows profit is a maximum of $582 per week when 12 R80 players and 54 G150 players are produced.

_____

Since the maximum profit is at a value of x less than 18, we didn't bother to graph that constraint.

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Answer:

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Volume then is increased by (\sqrt{2}l)^3 = 2\sqrt{2}l^3

1 :2 \sqrt{2}

Which is not an option in the question so this question clearly has a problem.

First of all It's supposed to be "then" not "than," so I'm not sure who teaches math without even knowing this basic grammar.

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3 years ago
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GREYUIT [131]

Answer:

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Step-by-step explanation:

I'm not really sure about this but no ones answering your question and I wanna help.

So basically to calculate the average speed you need to divide the distance travelled by time taken

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3 0
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Answer

Step by step explanation

7 0
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Answer:

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3 years ago
Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)
Marina86 [1]
<h2>Question :</h2>

<em>Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)</em>

<h2>Answer :</h2>

<em>y = -3/2x - 4 </em>

<h2>Explanation :</h2>

y = mx + c

*m = gradien

•>looking for gradients

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