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3 years ago

I NEED HELP ASAP. I WILL GIVE BRAINLYIST!! The speed of an object in space is shown in the graph.

Mathematics

1 answer:

zloy xaker [14]3 years ago

4 0

Answer:

3/2

rises by 3

runs by 2

I hope this is good enough:

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which of the following gives an equation of a line that passes through the point (6 over 5, -19 over 5) and is parallel to the l

victus00 [196]

One equation for this would be

$y = \frac{41}{16} x-\frac{55}{8}$

We start by finding the slope between the two points:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-12-\frac{-19}{5}}{-2-\frac{6}{5}}
\\
\\=(-12+\frac{19}{5}) \div (-2-\frac{6}{5})
\\
\\=(\frac{-60}{5}+\frac{19}{5}) \div (\frac{-10}{5}-\frac{6}{5})
\\
\\=\frac{-41}{5} \div \frac{-16}{5}=\frac{-41}{5} \times \frac{-5}{16}=\frac{41}{16}$

A line parallel to this one will have the same slope. We will use point-slope form to write our equation:

$y-y_1=m(x-x_1)
\\
\\y-\frac{-19}{5}=\frac{41}{16}(x-\frac{6}{5})
\\
\\y+\frac{19}{5}=\frac{41}{16}x- \frac{41}{16} \times \frac{6}{5}
\\
\\y+\frac{19}{5}=\frac{41}{16}x-\frac{246}{80}
\\
\\y+\frac{304}{80}=\frac{41}{16}x-\frac{246}{80}
\\
\\y=\frac{41}{16}x-\frac{246}{80}-\frac{304}{80}
\\
\\y=\frac{41}{16}x-\frac{550}{80}
\\
\\y=\frac{41}{16}x-\frac{55}{8}$

6 0

3 years ago

Cylinder shown is a steel tube that weighs 0.2835 pounds per cubic inch the inner part of the tubers hollow what is the height o

lesya [120]

Answer:

omg can someone answer i need to know

Step-by-step explanation:

5 0

3 years ago

Can someone help me?

VARVARA [1.3K]

Answer:

D. x=10, y=12

Step-by-step explanation:

7 0

3 years ago

The two dot plots below show the heights of some sixth graders and some seventh graders: The mean absolute deviation (MAD) for t

AysviL [449]

Answer:

The number of times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders is approximately 1.4

Step-by-step explanation:

From the question, the mean absolute deviation (MAD) of the sixth graders = 1.2 and that of the seventh graders = 1.7

The variability in the heights of the sixth graders = 1.2

The variability in the heights of the seventh graders = 1.7

To calculate how many times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders, we will divide the variability of the seventh graders by the variability of the sixth graders

That is, 1.7/ 1.2 = 1.4167 ≅ 1.4

Hence, the number of times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders is approximately 1.4

4 0

3 years ago

Find an equation for the hyperbola with center at origin (0,0), vertex (-6, 0) and focus

Katen [24]

-10 is the vertex dueeee

4 0

3 years ago