B=1260.
(according to your question on #11, stating a regular polygon with interior angles adding up to 1260)
By "<span>f(x = 2x + 1" you likely meant "f(x) = 2x + 1."
The given interval is [2,5], and so the width of each interval is (5-2)/n, or (3/n). Since we are using right end points, the x value at the right endpoint of the kth rectangle is 2+k(3/n). Examples: if k=1, the value at the right endpoint is 2+1(3/n); if k=2, 2+2(3/n), and so on. If k=n, then the value at the right endpoint is 2+n(3/n), or 2+3=5, which agrees with the given interval [2,5].
Once again, the given function is f(x) = 2x + 1.
At x = 2+k(3/n), the value of the function is 2[2+k(3/n)] + 1 (Answer). Check: If k=n, x = 2 + n(3/n) = 2+3 + 5, and f(5)=2(5) + 1 = 11.</span>
Answer:
The slope is easy to find, just take 4 numbers. 10-2/-12-5 = 5.16666667 rounded to the nearest whole number is 6. So, your slope is 6.
Step-by-step explanation:
P left triangle = (2x+8) + (2x+7) + 2x
combine like terms
P left =6x+15
P right triangle = 2x+ 2x+ (3x+7)
combine like terms
7x+7
since the perimeters of the triangles are equal, set them equal
6x+15 = 7x+7
subtract 6x from each side
15 =x+7
subtract 7 from each side
8 =x
AB = 2x+8 = 2*8 +8 = 16+8 = 24
BC =2x+7 = 2*8+7 = 16+7 = 23
CA = 2x =2*8 = 16
PQ = 2x = 16
QR = 2x = 16
PR = 3x+7 = 3*8+7 = 24+7 = 31
mean is when you add everything and then divide by the total amount of numbers there are. Add all the decimals and divide by 5.