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ycow [4]
2 years ago
9

What is an equation of the line that passes through the points (-4, 2) and (-8, -3)?

Mathematics
1 answer:
spin [16.1K]2 years ago
4 0
To find this use slope (m) for y2-y1/x2-x1
The find the y intercept by using the formula y-y1= m(x-x1)
Using these formulas the answer is
Y=1.25 or 5/4x+5
You might be interested in
Solve the systems by the addition method 2x + y = - 1x - 2y = - 4
inna [77]

Answer:

x = -6/5

y =7/5

Step-by-step explanation:

2x + y = - 1

x - 2y = - 4

Multiply the first equation by 2 so we can eliminate y

2(2x + y = - 1)

4x + 2y = -2

Add this to the second equation

4x + 2y = -2

x - 2y = - 4

---------------------

5x + 0y = -6

Divide by 5

5x/5 = -6/5

x = -6/5

Multiply the second equation by -2 so we can eliminate x

-2(x - 2y = - 4)

-2x+4y = 8

Add this to the first equation

2x + y = - 1

-2x+4y = 8

---------------------

0x + 5y = 7

Divide by 5

5y/5 = 7/5

y =7/5

6 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
What is the value of the expression below when x = 5 and y = 2?<br>X + 6y​
Vedmedyk [2.9K]
Instead of X put 5 and instead of y put 2
5+6(2)
5+12= 17
7 0
3 years ago
Find the equation of the line that contains the point (4,-2) and is perpendicular to the line y = – 2x + 5
velikii [3]

Answer:

--2

Step-by-step explanation:

hope this helps if not sorry

3 0
3 years ago
PLEASE HELP ME WITH THIS I WILL GIVE BRAINLIEST
vladimir2022 [97]

Answer:

1) 6+4x and 5+3x. 2) 3+6x and 10+2x. 3) 15+4x and 2+3x

Step-by-step explanation:

finding area is just multiplying the sides so find numbers that multiply to make 30 and 12

6 0
2 years ago
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