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ycow [4]
2 years ago
9

What is an equation of the line that passes through the points (-4, 2) and (-8, -3)?

Mathematics
1 answer:
spin [16.1K]2 years ago
4 0
To find this use slope (m) for y2-y1/x2-x1
The find the y intercept by using the formula y-y1= m(x-x1)
Using these formulas the answer is
Y=1.25 or 5/4x+5
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Question 2 pater romuli remique erat ______. question 2 options: 1) mars 2) numitor 3) amulius 4) pastor save question 3 which i
Mamont248 [21]
<span>"Pater romuli remique erat _______" translates as "The father of Romulus and Remus is____". The answer is 1) Mars. According to myth Rhea Silvia, who is the mother of the two brothers, claimed that the father of her children was the god Mars.</span>
3 0
3 years ago
What is 1/3 •1/3 in exponential notation
Zigmanuir [339]

Answer:

Step-by-step explanation:

1/3 x 1/3 in exponential notation is 1/3². you are multiplying a number by itself so its squared, ig you are multiplying a number by itself three times, then its cubed, with a 3.

6 0
3 years ago
898÷91,596 what is the answer
Dmitrij [34]

Answer:

For 100, your answer will be 102; For 898, your answer will be x; 100*x = 102*898 ... 102/x = 100/898 or x/102 = 898/100; x = 898*102/100 = 91596/100 = 915.96.

Hope this helps ∝

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7 0
2 years ago
Read 2 more answers
If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe
Natalka [10]

Answer:

They encircle the planet 3.76\times 10^{11} times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is 6.022\times 10^{23}

Thus, the number of dust particles is:

2.5\times 6.022\times 10^{23}=15.055\times 10^{23}

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: 10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m

If we line up the particles the distance they could cover is:

15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}

Circumference in meters:

40,076km\times \frac{1000m}{1km}=40,076,000 m

Therefore,

\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}

Hence, they encircle the planet 3.76\times 10^{11} times.

8 0
3 years ago
The number of lightning strikes in a year at the top of a particular mountain has a poisson distribution with a mean of 3.8. fin
atroni [7]

Let X be the number of lightning strikes in a year at the top of particular mountain.

X follows Poisson distribution with mean μ = 3.8

We have to find here the probability that in randomly selected year the number of lightning strikes is 0

The Poisson probability is given by,

P(X=k) = \frac{e^{-mean} mean^{x}}{x!}

Here we have X=0, mean =3.8

Hence probability that X=0 is given by

P(X=0) = \frac{e^{-3.8} 3.8^{0}}{0!}

P(X=0) = \frac{0.02237 * 1}{1}

P(X=0) = 0.0224

The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224

5 0
3 years ago
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