Answer:
Webmail allows the users to access their emails as long as they have access to an Internet connection and a web browser. This also means that the user cannot read an old email or draft a new email offline.
After he selects the Push transition, He should select from Left option from the Effect Options drop-down menu.
<h3>What is push transition in PowerPoint?</h3>
The Push Transition Effect is known to be a function in a PowerPoint that helps to pushes one slide to show the other.
Note that when this is applied to any presentation, it moves the current slide upwards to reveal the next slide and so on. A person can add use this kind of effect to present a scrolling effect to one's PowerPoint work.
Learn more about presentation from
brainly.com/question/24653274
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
They have different semantics, <span>addition to having different semantics from </span>double<span>, </span>int<span> arithmetic is generally faster, and the smaller size (32 bits vs. 64 bits) leads to more efficient use of caches and data transfer bandwidth.....
Did That Help You In Anyway </span>
Answer:1:navigate to the paragraph command group
2:Click the line and paragraph spacing option
3:Click the space required
Explanation:
