Answer:
#include <string>
#include <iostream>
using namespace std;
int main() {
string userInput;
getline(cin, userInput);
// Here, an integer variable is declared to find that the user entered string consist of word darn or not
int isPresent = userInput.find("darn");
if (isPresent > 0){
cout << "Censored" << endl;
// Solution starts here
else
{
cout << userInput << endl;
}
// End of solution
return 0;
}
// End of Program
The proposed solution added an else statement to the code
This will enable the program to print the userInput if userInput doesn't contain the word darn
Answer:
Eslabon Armando
His songs hit different ;-;
Answer:
The expression of this question can be given as:
Expression:
*ip + 1
Explanation:
In this question, it is given that ip variable has been declared and initialized and the ip variable is in the first half of the array. It finds the expression whose value is after the element of the array that ip points. So the expression to this question is *ip + 1. Where * is used to define ip variable as a pointer and its value is increased by 1 that is given in the question.
Answer:
Choose internet is the right answer
