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Alisiya [41]
3 years ago
6

At the fair concession stand, a drink costs $1.50, and a hot dog costs $2.75. If Jacob has $18 to spend on food, how many of eac

h item can he buy?
3 drinks and 7 hot dogs
3 drinks and 5 hot dogs
2 drinks and 7 hot dogs
2 drinks and 5 hot dogs
Mathematics
1 answer:
Cerrena [4.2K]3 years ago
6 0

Answer:

Answer is D (2 drinks and 5 hotdog's)

Step-by-step explanation: 1st answer is over as it is $19.25 for only the hotdogs. 2nd is $18.50 which is a little over. 3rd one is $22.25. And the forth one is $16.75 which is perfect because he cant buy anything else with the remainder of his money.

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If r(x)=3x-1 and s(x)=2x+1, which expression is equivalent to (r-s)(6)
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Answer:

4

Step-by-step explanation:

Step 1:  find (r- s) or  r(x) - s(x)

 r(x) - s(x) = 3x - 1 - (2x + 1)

       r(x) - s(x) = 3x - 1 - 2x - 1   (distribute the -1 to 2x and 1)

           r(x) - s(x) =  x - 2        (combine like terms, 3x + (-2x) = x, -1 + (-1) = -2)

          so   r(x) - s(x) = x - 2, or   (r - s)(x) = x - 2

Step 2:  Plug in 6 to 'x' and find (r - s)(x)

  (r - s)(6) =  6 - 2   =   4

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3 years ago
10q+5<br><br><br>I need the answer asap
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10q+<span>5
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Read 2 more answers
The random variable X~(30,2^2) <br> Find p(X&lt;33) <br> Find p(X&gt;26)
Ostrovityanka [42]

Answer:

i) P(X<33)  = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

<u>Step(ii):-</u>

i)

Given that the random variable  X = 33

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-30}{2} = 1.5 >0

P(X<33) = P( Z<1.5)

              = 1- P(Z>1.5)

             = 1 - ( 0.5 - A(1.5))

             = 0.5 + 0.4232

  P(X<33)  = 0.9232

<u>Step(iii) :-</u>

Given that the random variable  X = 26

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-26}{2} = 3.5 >0

P(X>26)  = P( Z>3.5)

              = 0.5 - A(3.5)

              = 0.5 - 0.4990

             = 0.001

P(X>26) = 0.001

5 0
3 years ago
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