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d1i1m1o1n [39]
3 years ago
5

If Paul takes 5 cookies from brenda she has 72 left how much cookies did she have?

Mathematics
1 answer:
Mandarinka [93]3 years ago
7 0

Answer:

She now has 67 cookies.

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The third term of an arithmetical progression is 7, and the seventh term is 2 more than 3 times the third term.Find the first te
Sphinxa [80]
General formula for n-th term of arithmetical progression is

a(n)=a(1)+d(n-1).

For 3d term we have

a(3)=a(1) +d(3-1),  where a(3)=7
7=a(1)+2d

For 7th term we have
a(7)=a(1) +d(7-1)
a(7)=a(1) + 6d

Also, we have that the <span>seventh term is 2 more than 3 times the third term,
a(7)=3*a(3)+2= 3*7+2=21+2=23

So we have, </span>a(7)=a(1) + 6d and a(7)=23. We can write
23=a(1) + 6d.

Now we can write a system of equations
23=a(1) + 6d
<span> - (7=a(1)+2d)
</span>
16 = 4d
d=4,

7=a(1)+2d

7=a(1)+2*4
a(1)=7-8=-1
a(1)= - 1

First term a(1)=-1, common difference d=4.

Sum of  the 20 first terms is
S=20 * (a(1)+a(20))/2

a(1)=-1
a(n)=a(1)+d(n-1)
a(20) = -1+4(20-1)=-1+4*19=75

S=20 * (-1+75)/2=74*10=740

Sum of 20 first terms is 740.
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It's easy just do the long way version do you know what way?
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Answer:

A

Step-by-step explanation:

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RideAnS [48]

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Step-by-step explanation:

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