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3 years ago

Prove that the diagonals of a rectangle bisect each other.

Mathematics

1 answer:

Umnica [9.8K]3 years ago

7 0

Answer:

Step-by-step explanation:

example A(2a,0),B(2b,0)

C(2b,2c),D(2a,2c)

mid point of AC=((2a+2b)/2,(0+2c)/2)=(a+b,c)

mid point of BD=((2b+2a)/2,(0+2c)/2)=(a+b,c)

∴midpoint of diagonals same or diagonals bisect each other.

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Step-by-step explanation:

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2 years ago

What is the area of this figure ?

PIT_PIT [208]

Remember that what you must do for this case is to calculate the area of the parallelogram and add it to the area of the rectangle.
 Palelogram area:
Knowing the base and the height, the area of the parallelogram is calculated by its formula:
A1 = b * h
We have then
b = root ((- 4 - (- 10)) ^ 2+ (2-2) ^ 2) = 6
h = root ((- 7 - (- 7)) ^ 2+ (3-2) ^ 2) = 1
A1 = (6) * (1) = 6 units ^ 2
Rectangle area
A2 = L * W
We have then:
L = root ((1 - (- 2)) ^ 2 + (- 3 - (- 4)) ^ 2) = 3.16227766
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Answer:
the area of this figure
A = 26 units ^ 2

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3 years ago

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Answer:

Step-by-step explanation:

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