Answer:
Step-by-step explanation:
Parallel lines have same slope.
y = mx + b
Slope = m & y-intercept = b
x - 5y = 15
-5y = -x + 15
y = 
so, slope = 1/5 ; (-5 , 7)
y -y1 = m(x -x1)
![y - 7 = \frac{1}{5}(x- [-5])\\\\y - 7 =\frac{1}{5}(x + 5)\\\\y - 7 = \frac{1}{5}x+5*\frac{1}{5}\\\\y - 7 =\frac{1}{5}x+1\\\\y =\frac{1}{5}x+1+7\\\\y=\frac{1}{5}x + 8](https://tex.z-dn.net/?f=y%20-%207%20%3D%20%5Cfrac%7B1%7D%7B5%7D%28x-%20%5B-5%5D%29%5C%5C%5C%5Cy%20-%207%20%3D%5Cfrac%7B1%7D%7B5%7D%28x%20%2B%205%29%5C%5C%5C%5Cy%20-%207%20%3D%20%5Cfrac%7B1%7D%7B5%7Dx%2B5%2A%5Cfrac%7B1%7D%7B5%7D%5C%5C%5C%5Cy%20-%207%20%3D%5Cfrac%7B1%7D%7B5%7Dx%2B1%5C%5C%5C%5Cy%20%3D%5Cfrac%7B1%7D%7B5%7Dx%2B1%2B7%5C%5C%5C%5Cy%3D%5Cfrac%7B1%7D%7B5%7Dx%20%2B%208)
16-3p =34. First you need to get the numbers and letters on different sides.
-16 -16
- 3p = 18 then divide by -3
__ __
-3 -3
p = -6 Hope that helps
1.5 because you do -16=-8x-4
+4 +4
-------------------------------------------------------
-12=-8x
---------------------------------------------
- 8 -8
-12/-8 equals 1.5
Answer:
3) directly above the package.
Step-by-step explanation:
The plane and the package carried by the plane are traveling with the same horizontal speed. When the package is dropped, a new vertical component of velocity is added to the package. The vertical velocity increases because of the acceleration due to gravity. The horizontal speed of the package remains the same. As long as the plane continues to fly at the same speed, the package hits the ground directly below the plane.
Answer: 3) directly above the package.
Answer:
For x(θ) = 3cosθ + 2
y² = [9x²/(x - 2)²] - x²
For x(θ) = 3cosθ + 2
x² = [4y²/(y - 1)²] - y²
Step-by-step explanation:
Given the following equivalence:
x² + y² = r²
r = √(x² + y²)
x = rcosθ
cosθ = x/r
y = rsinθ
sinθ = y/r
Applying these to the given equations,
x(θ) = 3cosθ + 2
x = 3(x/r) + 2
xr = 3x + 2r
(x - 2)r = 3x
r = 3x/(x - 2)
Square both sides
r² = 9x²/(x - 2)²
(x - 2)²r² = 9x²
(x - 2)²(x² + y²) = 9x²
(x² + y²) = 9x²/(x - 2)²
y² = [9x²/(x - 2)²] - x²
y(θ) = 2sinθ - 1
y = 2y/r - 1
yr = 2y - r
(y - 1)r = 2y
r = 2y/(y - 1)
Square both sides
r² = 4y²/(y - 1)²
x² + y² = 4y²/(y - 1)²
x² = [4y²/(y - 1)²] - y²
