No solution because everything cancels out
Answer:
option C.
Step-by-step explanation:
we have that
The point (-5,-12) belong to the III quadrant
so
The value of the cosine is negative
Applying the Pythagoras Theorem
Find the value of the hypotenuse
The value of cosine of angle θ is the ratio between the side adjacent to angle θ and the hypotenuse
Assuming the equation is x^2 + y^2 = 1, then that's a circle, with radius 1, centered on the origin [0,0].
So there are two tangents at x = 0. They are y = 1, and y = -1 (horizontal lines).
There is one tangent at x = 1. It is x = 1 (a vertical line).
There is no tangent at x = 35, because the original equation has no solution at x = 35.
B is just the y-intercept or where the line goes over the y axis so it would be 50
4= 121 5= 49 6= 169 hope this helps