Answer:
Step-by-step explanation:
From the given information:
(a)
Since growth quantity is not continuous

For t = 10


(b)
Here, for a continuous growth rate, the growth quantity can be computed in terms of initial quantity and the growth rate.
i.e.

At t = 10 for a continuous growth rate;



<span>The goal of writing a number in scientific notation is to have a decimal number, with one digit to theleft of the decmial point, followed by a × 10to some power.
</span><span>
To format your number in this way, we'll divide the 245,893 by 10, 2time(s), making it a 2.45.
We do this, because each division by 10 moves the decimal point to the left one digit.
But in order to keep our number the same number, we must have a × 102next to the 2.45.
</span><span>
So, the final answer is 2.45 × 10<span>2 (: Hope im right!</span></span>
The formula is V=Bh
You'd get the base (it's a circle so you'd have to do A=pie*radius square)
Once you find the base, you mutliply it by the height
there are 18 marbles all together
4 are red
18÷4= 4.5
percent 4.5%
fraction 4 1/2
decimal 4.5
I'm not sure about the second hald but I hope this helped ^^
If it has no x-intercept, it is a horizontal line going through 0,-2. hope this helps