3 years ago

Pls help with this question

Mathematics

1 answer:

katrin2010 [14]3 years ago

3 0

Answer:

We aren't going to do all your homework for you. That's why no one is answering. If you have one specific question, I can help

Step-by-step explanation:

. No one is going to do this whole assignment/homework.

You might be interested in

Dvinal [7]

Answer:

Help me with this please

7 0

3 years ago

30 people watched the soccer game last night tickets cost 2.75 each half of these fans bought a program at 1.50 each how much mo

Dima020 [189]

Answer: 105$
Half the ppl paid 1.50 for programs which is 15 x 1.5 = 22.5
30 ppl bought tickets 30x2.75
Add the totals to get 105

5 0

3 years ago

What is one third of 1296?

Kryger [21]

Answer:

four hundred thirty-two

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Solve (-5/2)x ‐ 5 = -55

Dmitry_Shevchenko [17]

Answer: 5

Step-by-step explanation: add 5 on each side and you get -50 then divide -5/2 with -50 and get 5

5 0

3 years ago

18. Brown eyes (B) are dominant to blue eyes (b). The presence of freckles (F) is dominant to the absence of freckles (f). What

MrRissso [65]

Answer:

For bbff we have only 6.3% probability

Step-by-step explanation:

If the parents are heterozygous for both traits, them they are represented by:

BbFf × BbFf

Parent 1: BbFf

Parent 2: BbFf

We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.

By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:

Genotype Count Percent

bBfF 4 25

BBfF 2 12.5

bBFF 2 12.5

bBff 2 12.5

bbfF 2 12.5

BBFF 1 6.3

BBff 1 6.3

bbFF 1 6.3

bbff 1 6.3

For bbff we have only 6.3% probability

6 0

3 years ago