Answer:
f(2) = 12
f(x) = 7, x = -3, 1
Step-by-step explanation:
<u>a)</u>
plug in x as 2
f(x) = 2^2 + 2(2) + 4
f(x) = 4 + 4 + 4
f(x) = 12
<u>b)</u>
replace f(x) with 7
7 = x^2 + 2x + 4
x^2 + 2x - 3 (move 7 to other side)
Factor
ac: -3x^2
b: 2x
split b into 3x, -x
(x^2 -x) + (3x - 3)
↓ ↓
x(x-1) + 3(x-1)
Factor: (x-1)(x+3) = 0
Solve using Zero Product Property:
x - 1 = 0, x + 3 = 0
x = 1, x = -3
I am assuming that we have to round the numbers to the nearest tens.
When rounding off numbers, if the number is more than half, then you round it up for example, if the number is 15 and you want to round it off, you round it up to 20. But if the number is 14 you round is down to 10
Therefore, 33 would be rounded off to 30 as 3 is less than 5 in the ones place if you get what I mean.
As for 89, you would round it up to 90 as the 9 in the ones place is more than 5.
Therefore the sum of 90 and 10 is 100.
Hope this helps!
Answer:
a
Step-by-step explanation:
Answer:
d. -10b-7
Step-by-step explanation:
74.4 is the answer.
hope this helps.
