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S_A_V [24]
4 years ago
5

Factor the polynomial below.

Mathematics
2 answers:
OverLord2011 [107]4 years ago
8 0

Answer:

option-A

Step-by-step explanation:

we are given

6b^2+3b

we can factor each terms

and then we can take common terms among them

6b^2=2\times 3\times b\times b

3b=1\times 3\times b

we can replace it

and we get

6b^2+3b=2\times 3\times b\times b +1\times 3\times b

now, we can take out common terms

we can see that common terms are 3 and b

6b^2+3b=3b(2\times b+1)

we can simplify it

6b^2+3b=3b(2b+1)

GREYUIT [131]4 years ago
4 0

Answer:

Its A.

Step-by-step explanation:

6b^2 + 3b.

The GCF is 3b so we divide this into the expression giving the factors:-

3b(2b + 1)  (answer).

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3 years ago
Can i get some help please
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Umm I am just guessing
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3 years ago
Read 2 more answers
Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl
Kazeer [188]

Answer: 10 ft

Explanation

As two right triangles (a triangle with a 90º angle) are formed, to know the distance between AB we have to calculate BC, AC and subtract.

0. Calculating BC

We have a 30º angle and an adjacent side 5√3ft (as the hypotenuse is the side opposite to the 90º angle). Thus, using the tangent function where:

\tan\theta=\frac{opposite}{adjacent}

we can find the opposite side, which is BC. Replacing the values and simplifying we get:

\tan(30\degree)=\frac{BC}{5\sqrt{3}}BC=5\sqrt{3}\tan(30\degree)BC=5ft

Thus, the segment BC measures 5ft.

<em>2. Calculating segment AC</em>.

In this case, our hypotenuse changes. However, we are still looking for the opposite side. Using the tangent function as before we get:

AC=5\sqrt{3}\tan(60\degree)AC=15

<em>3. Calculating the distance between A and B</em>

AC-BC=15-5=10ft

6 0
1 year ago
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